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2 years ago

13

Add these two velocity vectors to find the magnitude of their resultant vector. A. 4.6 meters/second B. 0.8 meters/second C. 2.2

meters/second D. 7.0 meters/second

1 answer:

Kay [80]2 years ago

5 0

Answer:a

Explanation:vector 2 will slow down vector 1 but vector 1 will still be going. i think.

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Are photons causing the electrons to flow off of the target? ( the target is calcium)

Sliva [168]

Answer:

The energy lost by the atoms is given off as an electromagnetic wave. ... even if it's not very intense, will always cause electrons to be emitted.

Explanation:

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3 years ago

Two objects with masses m and 3m are connected by a compressed spring so that the energy stored in the spring is 375 joules. If

cluponka [151]

Answer:

281.25 J

Explanation:

We are told that the two objects with masses m and 3m.

Also that energy stored in the spring is 375 joules.

Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3

Thus, from principle of conservation of energy, we have;

½mv² + ½(3m)(v/3)² = 375J

(m + 3m/9)½v² = 375

(4/3)m × ½v² = 375

Multiply both sides by ¾ to get;

½mv² = 375 × ¾

½mv² = 281.25 J

Therefore, energy of lighter body is 281.25 J

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2 years ago

A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him

juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal direction

$m_{b}v_{b}\cos\theta= m_{c}v_{c}$

$v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}$

Put the value into the formula

$v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}$

$v_{c}=0.0345\ m/s$

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0

3 years ago

Question 15 plz picture above

Pie

15) C. The amount of each element that begins....

8 0

3 years ago

A small, closed chamber of gas is heated. When the gas in the chamber expands,it does 5 J of work on a piston. The gas has an in

Anestetic [448]

Given:

Work done, W = 5 J

Initial energy = 8J

Final energy = 30J

Let's determine if the work done have a positive or nrgative value.

Appy the equation for the first lae of thermodynamics:

$\Delta U=Q-W$

Where:

U is the change in internal energy

Q is the added heat

W is the work done

To find the work done here, we have:

Rewrite the formula for W

$W=Q-\Delta U$

Where:

ΔU = 30J - 8J = 22J

Q = 5J

Thus, we have:

$\begin{gathered} W=5J-22J \\ \\ W=-17J \end{gathered}$

Therefore, the work done here is -17J.

This means the work done in this scenario has a negative value.

ANSWER:

The work done in this scenario has a negative value

3 0

1 year ago