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sergiy2304 [10]
3 years ago
12

What typ of dog is this (wrong answers only)

Engineering
2 answers:
MissTica3 years ago
8 0
Poodle lol this is fun
tangare [24]3 years ago
4 0
Great Dane look at the size of it
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Of the children who die in car crashes, how many of them die due to an improper restraint system (or even just not being buckled
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Answer:

you died

Explanation:

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Define the Artist class in Artist.py with a constructor to initialize an artist's information. The constructor should by default
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4 years ago
9.For a single-frequency sine wave modulating signal of 3 kHz with a carrier frequency of 36 MHz, what is the spacing between si
nikdorinn [45]

The spacing between sidebands is equal to 6 kHz.

<u>Given the following data:</u>

  • Modulating signal = 3 kHz.
  • Carrier frequency = 36 MHz.

<h3>What is a sideband?</h3>

A sideband can be defined as a band of frequencies that are lower or higher than the carrier frequency due to the modulation process. Thus, it will either be lower than or higher than the carrier frequency.

Generally, the frequency of the modulating signal is equal to the spacing between the sidebands. Therefore, a modulating signal of 3 kHz simply means that the lower sideband is <u>3 kHz</u> higher while the upper sideband is <u>3 kHz</u> lower.

Spacing = 3 kHz + 3 kHz = 6 kHz.

Read more on frequency here: brainly.com/question/3841958

8 0
2 years ago
What is the power system?
Inessa [10]

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4 0
4 years ago
A particle travels along a straight line with a velocity v = (12 – 3t2) m/s. When t = 1 s, the particle is located 10 m to the l
arlik [135]

Answer:

The displacement from t = 0 to t = 10 s,  is -880 m

Distance is 912 m

Explanation:

v = (12 - 3t^2) m/s = ds/dt.  .  . . . . . . . .  A

integrate above equation we get

s = 12t - t^3 + C

from information given in the question  we have

t = 1 s, s = -10 m

so distance s will be

-10 = 12 - 1 + C,

C = -21

s(t) = 12t - t^3 - 21

we know that acceleration is given as

a(t) = dv/dt = -6t  

[FROM EQUATION A]

Acceleration at  t = 4 s, a(4) = -24 m/s^2

for the displacement from t = 0 to t = 10 s,

s(10) - s(0) = (12*10 - 10^3 - 21) - (-21) = -880 m

the distance the particle travels during this time period:

let v = 0,

3t^2 = 12

t = 2 s

Distance = [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m

7 0
4 years ago
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