Answer:
The options a)- A blast furnace is used and d)-Coke is used to produce the heat are FALSE.
Explanation:
Aluminium is a chemical element and the most abundant metal present in the Earth's crust. An aluminium ore is called bauxite. Aluminium is extracted from its ore by the process of electrolysis, called the Hall–Héroult process. The extraction of aluminium is an expensive process as it requires large amount of electricity. The bauxite is purified to produce aluminium oxide. Then, aluminium is extracted from the aluminium oxide.
<u>Therefore, the refining of aluminum from its ore does not involve the use of a blast furnace and coke to produce heat.</u>
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Answer: E7018 is a low-hydrogen iron powder type electrode that produces high quality x-ray welds. It can be used in all positions on AC or DC reverse polarity welding current.
Explanation: Hope this helps
The lightning efficiency based on the scenario depicted will be C. 56 lumens/Watt, more efficient.
<h3>How to calculate the lightning efficiency</h3>
The efficiency of the incandescent bulb will be:
= 450/40 = 11.25 lumens per watt.
The efficiency of the LED bulb will be:
= 450/8 = 56 lumens per watt.
In this case, the LED bulb is more efficient than the incandescent bulb.
Therefore, the lighting efficiency will be 56 lumens/Watt, more efficient
Learn more lightning efficiency on:
brainly.com/question/25927632
Answer:
a.)
US Sieve no. % finer (C₅ )
4 100
10 95.61
20 82.98
40 61.50
60 42.08
100 20.19
200 6.3
Pan 0
b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4
c.) Cu = 3.33
d.) Cc = 1
Explanation:
As given ,
US Sieve no. Mass of soil retained (C₂ )
4 0
10 18.5
20 53.2
40 90.5
60 81.8
100 92.2
200 58.5
Pan 26.5
Now,
Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g
⇒ w = 421.2 g
As we know that ,
% Retained = C₃ = C₂×
∴ we get
US Sieve no. % retained (C₃ ) Cummulative % retained (C₄)
4 0 0
10 4.39 4.39
20 12.63 17.02
40 21.48 38.50
60 19.42 57.92
100 21.89 79.81
200 13.89 93.70
Pan 6.30 100
Now,
% finer = C₅ = 100 - C₄
∴ we get
US Sieve no. Cummulative % retained (C₄) % finer (C₅ )
4 0 100
10 4.39 95.61
20 17.02 82.98
40 38.50 61.50
60 57.92 42.08
100 79.81 20.19
200 93.70 6.3
Pan 100 0
The grain-size distribution is :
b.)
From the diagram , we can see that
D10 = 0.12
D30 = 0.22
D60 = 0.12
c.)
Uniformity Coefficient = Cu = 
⇒ Cu = 
d.)
Coefficient of Graduation = Cc = 
⇒ Cc =
= 1