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ruslelena [56]
3 years ago
11

PLEASE HELP! MAJOR TEST GRADE! :(

Chemistry
1 answer:
Goshia [24]3 years ago
7 0

Answer:

c

Explanation:

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4 years ago
If 87 grams of K2SO4 (molar mass 174 grams) is dissolved in enough water to make 250 milliliters of solution, what are the conce
guapka [62]

Answer:

M_{K^+}=4.0M \\\\M_{SO_4^{2-}}=2.0M

Explanation:

Hello!

In this case, since the molarity of a solution is defined as the moles of solute divided by the volume of solution liters, given the mass of potassium sulfate, we can compute the moles by using its molar mass (174.24 g/mol):

n_{K_2SO_4}=87gK_2SO_4*\frac{1molK_2SO_4}{174.27gK_2SO_4} =0.50molK_2SO_4

Thus, since one mole of potassium sulfate has two moles of potassium ions (K₂) and one mole of sulfate ions, we can compute the moles of each ion as shown below:

n_{K^+}=0.50molK_2SO_4*\frac{2molK^+}{1molK_2SO_4}=1.0molK^+\\\\ n_{SO_4^{2-}}=0.50molK_2SO_4*\frac{1molSO_4^{2-}}{1molK_2SO_4}=0.50molSO_4^{2-}\\

In such a way, the molarity of each ion turns out:

M_{K^+}=\frac{1.0mol}{0.250L}=4.0M \\\\M_{SO_4^{2-}}=\frac{0.5mol}{0.250L}=2.0M

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