When the entropy change of vaporization
= enthalpy of vaporization/boiling point temperature
when we have the enthalpy of vaporization = 38560 J/mol
and the boiling point temperature in Kelvin = 78.3 + 273 = 351.3 K
by substitution:
∴the entropy change of vaporization = 38560J/mol/351.3K
= 109.76 J/K/mol
and when the liquid has lesser entropy than the gas and we here convert from
gas to liquid so, the change in entropy = -109.76 J/K/mol
now, we need the moles of C2H5OH = mass/molar mass when the molar
mass of C2H5OH = 46 g/mol and mass = 42.2 g
∴ moles of C2H5OH = 42.2 g / 46 g/mol = 0.92 moles
when 1 mol of C2H5OH turns in liquid entropy change →-109.76 J/K/mol
∴ 0.92 mol of C2H5OH → X
∴ X entropy change when 0.92 mol = -109.76 *0.92 mol / 1 mol
= 84.64 J/K
When atoms share six electrons, they are joined by a double bond. (.5 points)
a. True
b. False?
Is False
Mass is the inside of an obeject such as what it’s made up of
Answer:
After 4 days 10 g will left
After 8 days 5 g will left.
Explanation:
Given data:
Half life of isotope = 4 days
Total amount of sample = 20 g
Amount left after each time period = ?
Solution:
The half life of radioactive isotope is 4 days it means after 4 days the amount left will be half of total amount.
20 g/2 = 10 g
The half amount which is left will be consume in next 4 days and remaining amount will be,
10 g/2 = 5 g
After 4 days 10 g will left
After 8 days 5 g will left.