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chubhunter [2.5K]
3 years ago
5

What element has a total of 3 p-sublevel electrons?

Chemistry
1 answer:
marishachu [46]3 years ago
3 0

Elements with three p-electrons....


That would be N, P, As, Sb, and Bi -- elements in group 15


For example, energy diagram showing "empty" orbitals up through the 3p.

.....3p __ __ __

3s __

.....2p __ __ __

2s __

1s __


Energy diagram of phosphorous showing three unpaired electrons in 3p-sublevel

.....3p ↑_ ↑_ ↑_

3s ↑↓

.....2p ↑↓ ↑↓ ↑↓

2s ↑↓

1s ↑↓


According to Hund's rule, the electrons singly occupy the p-orbitals, and all have the same spin.

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What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy
meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation  </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

The equation is:  

 \tt \Delta U=Q+W

Energy owned by the system is expressed as internal energy (U)  

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

\tt \Delta E=-13+5=-8~kJ

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3 years ago
Find the number of moles of argon in 364 grams of argon.
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Explanation:

364 g Ar x 1 mole Ar / 40 g Ar

= 9.1 moles Ar

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On may 10th it's gonna be my birthday and my mum don't know what to get me what do u think i would like my bio: creative,artisti
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2 years ago
What is the predominant intermolecular force in the liquid state of each of these compounds: ammonia (NH3), methane (CH4), and n
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Answer:

The  predominant intermolecular force in the liquid state of each of these compounds:

ammonia (NH3)

methane (CH4)

and nitrogen trifluoride (NF3)

Explanation:

The types of intermolecular forces:

1.Hydrogen bonding: It is a weak electrostatic force of attraction that exists between the hydrogen atom and a highly electronegative atom like N,O,F.

2.Dipole-dipole interactions: They exist between the oppositely charged dipoles in a polar covalent molecule.

3. London dispersion forces exist between all the atoms and molecules.

NH3 ammonia consists of intermolecular H-bonding.

Methane has London dispersion forces.

Because both carbon and hydrogen has almost similar electronegativity values.

NF3 has dipole-dipole interactions due to the electronegativity variations between nitrogen and fluorine.

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3 years ago
Which of the following reactions have a positive ΔSrxn? Check all that apply.
PolarNik [594]

Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

  • <em>2A(g) + B(s) → 3C(g)</em>

  • <em>2A(g) + 2B(g) → 5C(g)</em>

Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

  • <em><u>2A(g) + B(g) → C(g)</u></em>

Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>A(g) + B(g) → C(g)</em></u>

Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>2A(g) + 2B(g) → 5C(g)</em></u>

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

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