Answer:
A nucleophile view the full answer Question 3 (1 point) What is the first step in nucleophilic addition under acidic conditions? Protonation of the nucleophile Addition of the nucleophile Loss of water Protonation of the carbonyl
Explanation:
Answer:
HCl (aq) + NaOH (aq) --> H2O (L) + NaCl (aq)
Explanation:
HCl is a strong acid while NaOH is a strong alkali. Hence both should dissociate completely in water and 1 mol of HCl will fully neutralise 1 mol of NaOH.
I'm assuming that Part 2 on molarity is part of a data based question that requires you to calculate the number of moles of NaOH based on the data provided and the equation that you are required to balance. Hence, I can't help you with it as I do not have the values.
Answer:
Explanation:
Hello!
In this case, in a dilution process, water is added to a solute in order to decrease its concentration but increase the volume of the solution. It means that if we have 20.0 mL of a 12.0-M solution of HCl and we want a 0.500-M solution, we need to apply the following formula considering that the moles remain unchanged:
Thus, solving for the final volume is:
So plugging in the values we obtain:
Now, since the initial volume of acid was 20.0 mL and the final volume is 480 mL, the added volume of distilled water is:
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