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Kitty [74]
3 years ago
9

Where is tenessine on the periodic table?

Chemistry
1 answer:
Alla [95]3 years ago
8 0
Tenessine used to be called Ununseptium, however since it was only recently regarded as an actual element and the existence of the element has now been proven, it ended up receiving the name Tenessine. The atomic number is 117 and is in a Halogen.
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Neutrons have neither charge nor mass.<br> TRUE<br> FALSE
iren2701 [21]

Answer:

FALSE

nuetrons do indeed have no charge, however they are nearly 2000 more times massive than electrons.

7 0
2 years ago
Calculate the grams of C6H6 needed to produce 25 g of CO2<br> Show your work
Anna007 [38]

Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

M

M

C

O

2

=

44.01

g

/

m

o

l

M

M

C

6

H

6

=

78.11

g

/

m

o

l

and their mole ratio:

12

m

o

l

C

O

2

2

m

o

l

C

6

H

6

→

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

.

it is a problem of app

3 0
2 years ago
What is the mass of 8.23 x 10^23 atoms of Ag
Gnom [1K]

Answer:

\boxed {\boxed {\sf Approximately \ 147 \ g\ Ag}}

Explanation:

<u>Convert Atoms to Moles</u>

The first step is to convert atoms to moles. 1 mole of every substance has the same number of particles: 6.022 ×10²³ or Avogadro's Number. The type of particle can be different, in this case it is atoms of silver. Let's create a ratio using this information.

\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}

We are trying to find the mass of 8.23 ×10²³ silver atoms, so we multiply by that number.

8.23 *10^{23} \ atoms \ Ag *\frac{6.022*10^{23} \ atoms \ Ag}{1 \ mol \ Ag}

Flip the ratio so the atoms of silver cancel. The ratio is equivalent, but places the other value with units "atoms Ag" in the denominator.

8.23 *10^{23} \ atoms \ Ag *\frac{1 \ mol \ Ag}{6.022*10^{23} \ atoms \ Ag}

8.23 *10^{23}  *\frac{1 \ mol \ Ag}{6.022*10^{23} }

Condense into one fraction.

\frac{8.23 *10^{23}  }{6.022*10^{23} } \ mol \ Ag

1.366655596 \ mol \ Ag

<u>Convert Moles to Grams</u>

The next step is to convert the moles to grams. This uses the molar mass, which is equivalent to the atomic mass on the Periodic Table, but the units are grams per mole.

  • Ag: 107.868 g/mol

Let's make another ratio using this information.

\frac {107.868 \ g \ Ag}{1 \ mol \ ag}

Multiply by the number of moles we calculated.

1.366655596 \ mol \ Ag*\frac {107.868 \ g \ Ag}{1 \ mol \ ag}

The moles of silver cancel out.

1.366655596 *\frac {107.868 \ g \ Ag}{1 }

1.366655596 * {107.868 \ g \ Ag}

147.4184058 \ g\ Ag

<u>Round</u>

The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

  • 147.<u>4</u>184058

The 4 in the tenths place tells us to leave the 7 in the ones place.

147 \ g\ Ag

8.23 ×10²³ silver atoms are equal to approximately <u>147 grams.</u>

3 0
3 years ago
Balance the following equations: (c) H2(g)+I2(s)⟶HI(s)H2(g)+I2(s)⟶HI(s)
kenny6666 [7]

Answer: H_2(g)+I_2(g)\rightarrow 2HI(s)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Thus in the reactants, there are 2 atoms of hydrogen and 2 atoms of iodine .Thus there has to be 2 atoms of hydrogen and 2 atoms of iodine in the product as well. Thus a coefficient of 2 is placed in front of HI.

The balanced chemical reaction is:

H_2(g)+I_2(g)\rightarrow 2HI(s)

6 0
3 years ago
What is the mass of 4 × 1015 atoms of nickel<br> (Ni)?<br> Answer in units of g.
IRISSAK [1]

Answer:

4060

Explanation:

hope this helps

follow me for more answers

8 0
2 years ago
Read 2 more answers
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