Question

Consider an ideal gas contained in a cylinder with the volume 34.4L, temperature 667K and pressure 2atm.What will be pressure of the gas if it is heated at 1000k and the volume becomes 50L.

Answer 1

Given :

An ideal gas contained in a cylinder with the volume 34.4L, temperature 667K and pressure 2 atm.

To Find :

What will be pressure of the gas if it is heated at 1000k and the volume becomes 50L.

Solution :

We know, by ideal gas equation :

$Pv = nRT$

Now, in the given question only their are two state and also their is no leakage so amount of gas is also constant.

So,

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}\\\\\dfrac{2\times 34.4}{667} = \dfrac{P_2 \times 50}{1000}\\\\P_2 = \dfrac{2\times 34.4 \times 1000}{667 \times 50}\ atm\\\\P_2 = 2.06 \ atm$

Therefore, the pressure of gas is 2.06 atm.