Explanation:
Given that:
Distance traveled = 3150m
Average speed = 350m/min
Suggested speed = 375m/min
Unknown:
Time = ?
Solution:
Speed is the rate of change of distance with time.
it is mathematically expressed as;
speed = 
Initial time using speed 350m/min can be calculated by making time the subject of the formula;
time taken = 
time taken at speed of speed of 350m/min = 
= 9min
to seconds = 9 x 60 = 540 seconds
time taken at speed of 375m/min = 
= 8.4min
to seconds = 8.4 x 60 = 504 seconds.
It could have taken 504 seconds sooner saving 36 seconds.
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Answer:
<em><u>spontaneous composition</u></em> is the ingnition
of the substance due to the repid oxidation of its on material.
There is no requirement of heat of external sources.
<em><u>Rapid composition</u></em> on the other hand release large amount of heat and light energy.
Explosion and the firecracker is the best example of Rapid composition.
Answer: i could be incorrect but im pretty sure the answer is, Gas surface with no rings.
Explanation:
s-s-s-science!
Answer:
Explanation:
Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.
In 1897, J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.
Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.
The Bohr model shows the atom as a small, positively charged nucleus surrounded by orbiting electrons. Bohr was the first to discover that electrons travel in separate orbits around the nucleus and that the number of electrons in the outer orbit determines the properties of an element.
Answer:
0.35 atm
Explanation:
It seems the question is incomplete. But an internet search shows me these values for the question:
" At a certain temperature the vapor pressure of pure thiophene (C₄H₄S) is measured to be 0.60 atm. Suppose a solution is prepared by mixing 137. g of thiophene and 111. g of heptane (C₇H₁₆). Calculate the partial pressure of thiophene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal."
Keep in mind that if the values in your question are different, your answer will be different too. <em>However the methodology will remain the same.</em>
First we <u>calculate the moles of thiophene and heptane</u>, using their molar mass:
- 137 g thiophene ÷ 84.14 g/mol = 1.63 moles thiophene
- 111 g heptane ÷ 100 g/mol = 1.11 moles heptane
Total number of moles = 1.63 + 1.11 = 2.74 moles
The<u> mole fraction of thiophene</u> is:
Finally, the <u>partial pressure of thiophene vapor is</u>:
Partial pressure = Mole Fraction * Vapor pressure of Pure Thiophene
- Partial Pressure = 0.59 * 0.60 atm
