We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
Answer:

Step-by-step explanation:
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Given:

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Collect like terms.

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Simplify

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Hope this is helpful.
Answer:
{-2, -1, 1, 5, 6}
Step-by-step explanation:
The domain includes the five x-values (inputs): {-2, -1, 1, 5, 6}
Answer:
7(2)+7(5) {using distributive property}
14+35 {7 multiplied by 2 gives 14 and 7 multiplied by 5 gives 35}
49 {therefore 35+14 gives 49}
Step-by-step explanation:
Your answer is 49
Hope this helps :)
Y = 2x - 4
You need to take everything except y to the LHS to get the equation into the form of y = mx + c