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3 years ago

Select the correct answer.

Mathematics

2 answers:

Ghella [55]3 years ago

8 0

Answer:x-5

Step-by-step explanation:

creativ13 [48]3 years ago

6 0

Answer:

I took the test and it is not -5. I don'tknow what it is though

Step-by-step explanation:

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If a and b are non-negative integers, is ab prime?

andrew-mc [135]

No because ab can be divided by a and b.

8 0

3 years ago

Simplify

Fantom [35]

2+5=7
7-3=4
so the answer is b

6 0

3 years ago

Franklin has three coins, two fair coins (head on one side and tail on the other side) and one two-headed coin. He randomly pick

Rainbow [258]

Answer:

<h2> B and C are not independent events </h2>

Step-by-step explanation:

This is a probability question, basically on independent events.

B and C are said to be independent if the occurrence of either event does not affect the occurrence of the other.

And now considering the fact that C will always present a head any way anyhow, the occurrence

of C will affect the outcome of B and C.

<em>Hence B and C are not independent events</em>

6 0

3 years ago

The weights of newborn babies are distributed normally, with a mean of approximately 105 oz and a standard deviation of 10 oz.

Assoli18 [71]

Answer: 0.9987

Step-by-step explanation:

Given : The weights of newborn babies are distributed normally, with a mean of approximately 105 oz and a standard deviation of 10 oz.

i.e. $\mu=105\ oz$ and $\sigma= 10\ oz$

Let x represents the weights of newborn babies.

If a newborn baby is selected at random, then the probability that the baby weighs more than 75 oz will be :-

$P(x>75)=P(\dfrac{x-\mu}{\sigma}>\dfrac{75-105}{10})\\\\ =P(z>-3 )=P(z-z)=P(Z$

$=0.9987$ [using z-value table]

Hence, the required probability = 0.9987

8 0

3 years ago

Sheldon spins the two spinners below one time what are the chance he will spin 3 or c ?

Nostrana [21]

Answer:

$P(3\ or\ c) = 0.45$

Step-by-step explanation:

Given

See attachment for spinner

Required

$P(3\ or\ c)$

From the first spinner, we have:

$S = \{1,2,3,4,5\}$ --- Sample Space

$n(S)=5$

So, P(3) is:

$P(3) = \frac{n(3)}{n(S)}$

$P(3) = \frac{1}{5}$

$P(3) = 0.20$

From the second spinner, we have:

$S = \{a,b,c,d\}$

$n(S) = 4$

So, P(c) is:

$P(c) = \frac{n(c)}{n(S)}$

$P(c) = \frac{1}{4}$

$P(c) = 0.25$

The required probability is then calculated as:

$P(3\ or\ c) = P(3) + P(c)$

$P(3\ or\ c) = 0.20 + 0.25$

$P(3\ or\ c) = 0.45$

8 0

2 years ago