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4 years ago

URGENT, ALL HELP ACCEPTED PLEASE! Solve y= 3x-1 and (1/2)y+x=1 for their COMMON solution.

1 answer:

6 0

Simplify the second equation.

1/2y = -x + 1

Multiply both sides by 2

y = -2x + 2

Since both equations equal y you can set them equal to each other.

-2x + 2 = 3x - 1

Solve for X

-5x = -3

x = 3/5

Plug this into one of the equations.

3(3/5) - 1 = y

1.8 - 1 = y

y = .8

(0.6, 0.8)

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

In this exercise, consider a particle moving on a circular path of radius b described by r(t) = b cos(ωt)i + b sin(ωt)j, where ω

Bingel [31]

Answer:

Acceleration of the particle = $bw^{2}$

Step-by-step explanation:

We are given the position vector of a particle moving in a circle of radius b units.

r(t) = b cos(ωt)i + b sin(ωt)j

Velocity , v = $\frac{dr}{dt}$ = -bω sin(ωt)i + bω cos(ωt)j

The magnitude of velocity, v = $\sqrt{v_x^{2} +v_y^{2} }$

Squaring both sides,

$v^{2} = b^{2} w^{2}(sin^{2}(wt)+cos^{2}(wt))$

Since $sin^{2}(wt)+cos^{2}(wt))$ = 1

$v^{2} = b^{2}w^{2}$

The acceleration towards the centre is called the centripetal acceleration and is given by

a = $\frac{v^{2} }{r}$

a = $\frac{b^{2}w^{2}}{b}$

a = $bw^{2}$

3 0

3 years ago

For the following trapezoid, h = 5 ft, b = 7.9 ft, and B = 14.6 ft. What is the area?

Bond [772]

Answer:

The area of the trapezoid is 56.25² feet.

Step-by-step explanation:

The formula for the area of a trapezoid is $A=\frac{b+B}{2} h$

A = area (of the trapezoid)
b = base of the trapezoid
B = (other) base of the trapezoid
h = height of the trapezoid

*Note: Trapezoids have 2 bases that are parallel to one another, but are not always the same length.

Using the information given to us, we can simply plug in numbers into the equation. By doing so, we'd get $A=\frac{7.9+14.6}{2} 5$ . By plugging this into a calculator, you'd get $A=56.25$ .

3 0

2 years ago