Find the product
(2n-2)(2n^2-3n+5)
1 answer:
Answer:
4n^3 -10n^2 +16n -10
Step-by-step explanation:
Use the distributive property to eliminate parentheses, then combine like terms.
= 2n(2n^2 -3n +5) -2(2n^2 -3n +5)
= 4n^3 -6n^2 +10n -4n^2 +6n -10
= 4n^3 +n^2(-6-4) +n(10+6) -10
= 4n^3 -10n^2 +16n -10
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