Question

Find the product (2n-2)(2n^2-3n+5)

Answer 1

Answer:

  4n^3 -10n^2 +16n -10

Step-by-step explanation:

Use the distributive property to eliminate parentheses, then combine like terms.

  = 2n(2n^2 -3n +5) -2(2n^2 -3n +5)

  = 4n^3 -6n^2 +10n -4n^2 +6n -10

  = 4n^3 +n^2(-6-4) +n(10+6) -10

  = 4n^3 -10n^2 +16n -10