3 years ago

Find the product (2n-2)(2n^2-3n+5)

Mathematics

1 answer:

atroni [7]3 years ago

4 0

Answer:

4n^3 -10n^2 +16n -10

Step-by-step explanation:

Use the distributive property to eliminate parentheses, then combine like terms.

= 2n(2n^2 -3n +5) -2(2n^2 -3n +5)

= 4n^3 -6n^2 +10n -4n^2 +6n -10

= 4n^3 +n^2(-6-4) +n(10+6) -10

= 4n^3 -10n^2 +16n -10

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