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Alina [70]
3 years ago
13

Write the ratio as a fraction in simplest form, with whole numbers in the numerator and the denominator. 12 mi to 28 mi

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

3/7

Step-by-step explanation:

12 ÷ 4

28 ÷ 4

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Given that cos 57° = 0.545, enter the sine of a complementary angle.<br> sin<br> h
noname [10]

Answer:

sin 33° = 0.545

Step-by-step explanation:

complementary angle to 57° is 33°

sin 33° = 0.545

4 0
3 years ago
Solve for X and Y <br><br> I will mark brainliest !!
viktelen [127]

Answer:

X=24, Y=7

Step-by-step explanation:

We use the concept of similarity.

By observing the figure, we notice that the hypotenuse is 50, and the hypotenuse of the smaller triangle is 25.

That means the hypotenuse of the larger triangle is double the hypotenuse of the smaller triangle. Meaning, the other sides of the larger triangle would be double the smaller sides of the smaller triangle.

We already have the sides of the larger triangle, divide them by two to get x and y.

X = 48/2 = 24

Y = 14/2 = 7

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3 years ago
Please help! Big grade! Extra points!! Help asap!
Sonbull [250]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is algebra 1 and 2
telo118 [61]
Algebra 1 is a basic algebra course usually taken in freshman year (9th grade). Common Core guidelines dominate the curriculum. It is faster paced than middle school math courses. Algebra 2 is a more advanced algebra course usually taken in junior year (11th grade). Algebra 2 is paced even faster and builds on what you learn in A1 and geometry. Both deal with variables and the manipulation of numbers.
7 0
3 years ago
22.
Vlada [557]

Step-by-step explanation:

\sqrt{p}  =  \sqrt[r]{w -  {as}^{2} }

Find raise each side of the expression to the power of r

That's

<h2>( \sqrt{p} )^{r}  =  (\sqrt[r]{w -  {as}^{2} } ) ^{r}</h2>

we have

<h2>( \sqrt{p} )^{r}  =  w -  {as}^{2}</h2>

Send w to the left of the equation

<h2>( \sqrt{p} )^{r}  - w =  -{as}^{2}</h2>

Divide both sides by - a

We have

<h2>{s}^{2}  =  -\frac{( \sqrt{p} )^{r}  - w}{a}</h2>

Find the square root of both sides

We have the final answer as

<h2>s =  \sqrt{ -\frac{( \sqrt{p} )^{r} - w }{a} } </h2>

Hope this helps you

3 0
3 years ago
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