It will take 6 years for that to happen.
You can find this by setting Nichole's age as x and Sophie's age as x + 28 since she will always be 28 years older.
Now we are looking for a time that Sophie's age is equal to 2 less than 6 times Nichole's age. So we can set up the below equation.
6(x) - 2 = x + 28
6x - 2 = x + 28
5x - 2 = 28
5x = 30
x = 6
This let's us know that it needs to be when Nichole is 6, which is 6 years in the future.
You have to factor by grouping.
(4a - 5) (a + 4)
We have an arithmetic sequence with
<span>a0 = 1st 3-digit number divisible by 13 </span>
<span>a0 = 104 </span>
<span>d = 13 (why?) </span>
<span>last term is largest divisible by 13 = 988 </span>
<span>how many terms? (988-104)/13 + 1 = 69 </span>
<span>S = 69/2(104+988) = 37674</span>
Answer:
h'(1)=0
Step-by-step explanation:
We use the definition of the derivative of a quotient:
If 
, then:
Since in our case we want the derivative of 
at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:
which, by replacing with the given numerical values:
becomes:
