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GREYUIT [131]
3 years ago
12

243 log 3^4x = 48 , x=...

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0
243log(81x)=48
log(81x)=48÷243
log(81x)=16÷81
81x=10^(16÷81)
81x= 81sqaure root pf 10^16
divide by 81
x =.0194557
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The relation R is shown below as a list of ordered
Dmitrij [34]

Answer:

(1, 4) and (1,3), because they have the same x-value

Step-by-step explanation:

For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.

In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.

Therefore, the relation is not a function anymore if both ordered pairs are included.

<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>

7 0
2 years ago
Help <br> A)40 <br> B)50 <br> C)130
omeli [17]

Answer:

40

Step-by-step explanation:

180 -40 - 90 = 50

I don't remember the name of the type of angle, but since that one angle is 50 the other side is also 50.

180 - 90 - 50 = 40

Tell me if I am wrong.

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8 0
3 years ago
A television costs $610 this week after costing $745 last week. What was
diamong [38]
It was an increase of 15%
5 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.) <br> e2x 25 e4x dx.
Sladkaya [172]

Answer:

The solution is  \frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

Step-by-step explanation:

From the question

    The function given is  f(x) =  \frac{e^{2x}}{ 25 + e^{4x}} dx

The  indefinite integral is  mathematically represented as

          \int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx

Now  let  e^{2x} =  u

=>   \frac{du}{dx} 2e^{2x}

=>   2 e^{2x}dx =  du

So

\int\limits  {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx =  \int\limits  {\frac{1}{ 2(25 + u^2)} } \, du

= \frac{1}{2} \int\limits  {\frac{1}{ 25 + u^2)} } \, du

=  \frac{1}{2} \int\limits  {\frac{1}{ 5^2 + u^2)} } \, du

= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5}  +  C

Now substituting for  u

\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] +  C

3 0
3 years ago
There are 5 times as many yellow labs as terriers in the dog park. if there are a total of 18 dogs, how many dogs are terriers?
gtnhenbr [62]
Terriers = x
Labs = 5x
5x + x = 18
6x = 18
6x / 6 = 18/6
x = 3
There are 3 Terriers
3 0
3 years ago
Read 2 more answers
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