Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle =
Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
Answer:
area of a circle πr^2
r = 10/2 r = 5
π5^2 = 78.5
area of the square length X width
7 x 7 = 49
78.5 - 49 = 29.5
shaded region = 29.5 square cm
The correct answer of the given question above would be 8ft/sec. The minimum speed that the stone be thrown so as to reach a height of 49 feet is 8ft/sec. Consider this given solution here:
u^2 = 2x a x 1
<span>u^2 = 2 x 32 x 1 </span>
<span>u = 8 ft/sec
</span>Hope this answer helps and this is what you are looking for.
All we have to do is replace n with 4.
-6-4(4-1)
Parenthesis first.
-6-4×3
Multiplication next.
-6-12
Now subtract.
-18
The 4th term is -18.
Tell me if this helps!!