Find the missing angle x. Round to the nearest whole number.

Helena needs 3.5 cups of flour per loaf of bread and 2.5 cups of flour per batch of muffins. She also needs 0.75 cup of sugar pe

vesna_86 [32]

Let
x = loaves of bread
y = batches of muffins
You must make a system of two equations with two unknowns that describe the problem
3.5x + 2.5y = 17 --- (1)
0.75x + 0.75y = 4.5 --- (2)
Resolving we have
x = 6-y (from (2))
replacing in (1)
3.5 (6-y) + 2.5y = 17
21 - 3.5y + 2.5y = 17
y = 21-17 = 4
Then substituting in (2)
x = 6-y = 6-4 = 2
Answer
Helena could bake:
2 loaves of bread
4 batches of muffins

8 0

3 years ago

Please Help this is Due in 1 hour and I really dont understand any of this. (Question in Image)

KATRIN_1 [288]

Answer:

Step-by-step explanation:

4 0

3 years ago

CAN SOMEONE PLEASE HELP

Allushta [10]

4 is the right answer

4 0

2 years ago

Read 2 more answers

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .