1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madam [21]
3 years ago
10

Helpppp :) 50 points

Mathematics
2 answers:
netineya [11]3 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

A only 1 solution

B

4(2x - 5) = 4 ( divide both sides by 4 )

2x - 5 = 1 ( add 5 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

tensa zangetsu [6.8K]3 years ago
4 0

Answer:

  • \boxed{\sf{x=3}}

Step-by-step explanation:

Isolate it by the term of x from one side of the equation.

  • Part A. There will be one solution.
  • Part B.

<h3>4(2x-5)=4</h3>

<u>First, divide by 4 from both sides.</u>

\sf{\dfrac{4\left(2x-5\right)}{4}=\dfrac{4}{4}}

<u>Then, solve.</u>

4/4=1

<u>Rewrite the problem down.</u>

2x-5=1

<u>Add by 5 from both sides.</u>

\sf{2x-5+5=1+5}

Solve.

1+5=6

2x=6

<u>Divide by 2 from both sides.</u>

2x/2=6/2

<u>Solve.</u>

<u>Divide the numbers from left to right.</u>

6/2=3

<u>x=3</u>

  • Therefore, the correct answer is x=3.

I hope this helps you! Let me know if my answer is wrong or not.

You might be interested in
4.) write a number that is a natural number<br> 5.) write a number that is an irrational number
Bad White [126]
Natural number - 5
Irrational number - π
7 0
3 years ago
Read 2 more answers
The mean sustained wind velocity, v, can be determined by the equation , where p is the air pressure, in millibars, at the cente
inn [45]

The mean sustained wind velocity has the equation:

v = 6.3 √(1013 - p)


If we are given with the mean sustained wind velocity of 64 m/s, then we can solve for the air pressure using the equation:

64 = 6.3 √(1013 - p)

64/6.3 = √(1013 - p)

10.1587² = 1013 - p

p = 910 millibars


hope this helps!!!!!!!!!!!!


8 0
3 years ago
Read 2 more answers
The sequence an = one third(3)n − 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average
Maru [420]
The given sequence is:

a(n)= \frac{1}{3}  (3)^{n-1}

a(2)=1
a(3)=3
a(4)=9

We are to find the average rate of change between n=3 and n=4 for the given function.

Average rate of change = \frac{a(4)-a(3)}{4-3} = \frac{9-3}{1}=6

So the average rate of change for the given function from n = 3 to n = 4 is 6
8 0
3 years ago
Read 2 more answers
Find the distance between the two points in simplest radical form.
adoni [48]

Answer:

y=−2/5x+4/5y

Step-by-step explanation:

Hope's this helps

6 0
3 years ago
Lily invested $90,000 in an account paying an interest rate of 4.6% compounded
kondaur [170]

Answer:

20 years. ($221,246.39, to be exact.)

Step-by-step explanation:

Compound interest is a system where the interest rate always applies for the amount you first put your money in. So if you put 90,000 dollars as your first deposit, the annual interest would only apply to $90,000 every time.

8 0
3 years ago
Other questions:
  • what do I put on the blank spots that have parenthesis and a plus sign in the middle? its number 15 that's talking about 56 and
    6·1 answer
  • Evaluate -4 +(-3) - (-2)
    15·2 answers
  • A cafeteria was putting milk cartons into stacks. They had nine hundred twenty-six cartons and were putting them into stacks wit
    13·1 answer
  • The volume of a spherical hot air balloon v(r) = 4 3 πr3 changes as its radius changes. the radius is a function of time given b
    11·1 answer
  • Plz help meee thx love you
    9·1 answer
  • I need help with this math please.
    11·1 answer
  • Use SAS to explain why ∆XYZ ≅ ∆VWZ !!!!!!!!!! Answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!
    13·1 answer
  • Find the square of (a+b+c)​
    6·1 answer
  • Question 7: 10 pts
    13·1 answer
  • For the inequality: <br> 6_&gt; x +2y<br> Is (-1,-2) a solution
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!