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3 years ago

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Explain how to write a quadratic equation given the vertex and another point on the graph, in the form of ()=(−ℎ)2+, vertex form

.
Vertex: (−4,6)and point (−3,3)

1 answer:

Inessa05 [86]3 years ago

8 0

4,3 would be the answer for this one to do it and get its

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T(x)=1-2x how do you graph this problem

Eva8 [605]

Answer:

Explained

Step-by-step explanation:

The 1 is the y-intercept

The -2 is the slope

First place a point at (0,1)

Then, because it's negative from left to right the graph is decreasing (going lower on the y-axis the farther you go on the x-axis).

Slope is rise over run so the -2 affects how far it goes. So for each value of x that increases by one, a new point will be two units down and one unit right of the previous point. To graph to the left of the y-intercept then you do that backwards where the next point is two units up and one unit left.

Then just draw a straight line connecting all the points.

7 0

3 years ago

The table shows Mitch’s record for the last thirty par-3 holes he has played.

nlexa [21]

Answer:c. 3/10

Step-by-step explanation:

4 0

3 years ago

According to the National Oceanic and Atmospheric Administration, the blue whale is the largest animal on Earth. Blue whales wei

never [62]

Answer: The blue whale's weight is 150 times heavier than the narwhal's weight.

Step-by-step explanation:

Given: Weight of Blue whale = $3\times10^5\text{ pounds}$

Weight of Narwhal = $2\times10^3\text{ pounds}$

Number of times blue whale's weight is heavier than the narwhal's weight = $=\dfrac{\text{Weight of Blue whale}}{\text{Weight of Narwhal }}$

$=\dfrac{3\times10^5}{2\times10^3}\\\\=1.5\times10^{5-3}\ \ \ [\dfrac{a^m}{a^n}=a^{m-n}]\\\\=1.5\times10^2\\\\=1.5\times100=150$

Hence, the blue whale's weight is 150 times heavier than the narwhal's weight.

5 0

3 years ago

Prove: cos(3x)=sin(2x)

Vesnalui [34]

Answer:

Step-by-step explanation:

Step-by-step explanation:

By taking ( x = 18°)

<u>L.H.S</u>

cos(3x)=sin(2x)

cos(3x) = cos( 3X18°)= cos (54°)

= cos[ 90° - (2x18°)] ∵[ 90°- (2x18°) = 54°]

= ∴ sin ( 2x18°)

As (x = 18°)

= sin (2x) = R.H.S

7 0

3 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0

3 years ago