Can I have the answer please

When a hammer thrower releases her ball, she is aiming to maximize the distance from the starting ring. Assume she releases the

Taya2010 [7]

Answer:

The angular velocity is 15.37 rad/s

Solution:

As per the question:

$\theta = 54.6^{\circ}$

Horizontal distance, x = 30.1 m

Distance of the ball from the rotation axis is its radius, R = 1.15 m

Now,

To calculate the angular velocity:

Linear velocity, v = $\sqrt{\frac{gx}{sin2\theta}}$

v = $\sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}$

v = $\sqrt{\frac{294.98}{sin109.2^{\circ}}} = 17.67\ m/s$

Now,

The angular velocity can be calculated as:

$v = \omega R$

Thus

$\omega = \frac{v}{R} = \frac{17.67}{1.15} = 15.37\ rad/s$

8 0

3 years ago

A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0

Elodia [21]

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

8 0

3 years ago

What is the displacement of the runner in 4 laps? * 2 point

Serhud [2]

Answer:

There is no displacement.

Explanation:

Because the runner is running laps and returning to the original place, there is no displacement as displacement is relative to the change in location from the original position.

Hope this helps. . .

ly UwU

3 0

2 years ago

A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 36.5 m/s. At the same time, it h

sammy [17]

Answer:

66.26 m/s

Explanation:

Horizontal velocity, Vx = 55.3 m/s

Vertical velocity, Vy = 36.5 m/s

The value of the resultant velocity is given by the vector sum of the two velocities which are acting at 90°.

$V=\sqrt{V_{x}^{2}+V_{y^{2}}}$

$V=\sqrt{55.3^{2}+36.5^{2}}}$

V = 66.26 m/s

Thus, the velocity of the vehicle is 66.26 m/s along its descent path.

5 0

2 years ago

What is the spring potential energy of a spring that is stretched 15 cm if its spring constant is 350 n/m?

VladimirAG [237]

Answer:

Spring potential energy = 7.875Nm

Explanation:

Given the following data;

Extension, e = 15cm to meters = 15/100 = 0.15m

Spring constant, k = 350n/m

To find the force;

Force = spring constant * extension

Force = 350 * 0.15

Force = 52.5 Newton.

Now to find the spring potential energy we would use the formula below;

Spring potential energy = force * extension

Substituting into the equation, we have;

Spring potential energy = 52.5 * 0.15

Spring potential energy = 7.875Nm

6 0

3 years ago