D.
Solar energy is converted to wind energy which then drive surface currents.
Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
![r= \sqrt{\frac{Gm1m2}{F} }](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%7B%5Cfrac%7BGm1m2%7D%7BF%7D%20%7D)
![r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%7B%5Cfrac%7B6.67430%2A10%5E-11%2A900%2A1600%7D%7B0.0001%7D%20%7D%5C%5C%5C%5Cr%3D%200.00009610992%2F0.0001%60%7D%5C%5C%5C%5Cr%3D%200.96m)
Answer:
The distance is 0.96m
Explanation:
Given
m1= 900kg
m2= 1600kg
Force F= 0.0001nN
G=6.67430*10^-11 Nm^2/kg^2
Required:
The distance r
Step two:
the formula for the force is given as
F = Gm1m2/r2
make r subject of the formula
![r= \sqrt{\frac{Gm1m2}{F} }](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%7B%5Cfrac%7BGm1m2%7D%7BF%7D%20%7D)
![r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m](https://tex.z-dn.net/?f=r%3D%20%5Csqrt%7B%5Cfrac%7B6.67430%2A10%5E-11%2A900%2A1600%7D%7B0.0001%7D%20%7D%5C%5C%5C%5Cr%3D%200.00009610992%2F0.0001%60%7D%5C%5C%5C%5Cr%3D%200.96m)
The quantity of matter in a body regardless of its volume or of any forces acting on it.
-- As she lands on the air mattress, her momentum is (m v)
Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down
-- As she leaves it after the bounce,
Momentum = (60 kg) (1 m/s up) = 60 kg-m/s up
-- The impulse (change in momentum) is
Change = (60 kg-m/s up) - (300 kg-m/s down)
Magnitude of the change = <em>360 km-m/s </em>
The direction of the change is <em>up /\ </em>.