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Vlad1618 [11]
2 years ago
8

A single-turn circular loop of wire that has a radius of 5.0cm lies in the plane perpendicular to a spatially uniform magnetic f

ield. During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2T to 0.4T. determine the magnitude of the emf induced in the loop during the time interval.
Physics
1 answer:
Pavlova-9 [17]2 years ago
5 0

Answer:

Induced emf will be 0.01308 volt

Explanation:

We have given the radius of the circle r = 5 cm = 0.05 m

We know that area of the circle is given by A=\pi r^2=3.14\times 0.05^2=78.5\times 10^{-4}m^2

The magnetic field is changes from 0.2 T to 0.4 T

So change in magnetic field dB = 0.4 - 0.2 = 0.2 T

Time is given as dT = 0.12 sec

We know that induced emf is given by

e=A\frac{dB}{dT}=78.5\times 10^{-4}\times \frac{0.2}{0.12}=0.01308Volt

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Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

mv_{1i}+Mv_{2i}=(m+M)v  (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

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Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive
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Answer:

The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

Explanation:

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Diameter = 10 light year

Orbital speed = 180 km/s

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Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

r=\dfrac{d}{2}

r=\dfrac{15\times9.461\times10^{15}}{2}

r=7.09\times10^{16}\ m

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

M=\dfrac{v^2r}{G}

Put the value into the formula

M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}

M=3.44\times10^{37}\ Kg

Hence, The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

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