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2 answers:
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Answer:
- Orange juice: 125 mg
- Cranberry juice: 90 mg
Step-by-step explanation:
For the first question/part:
- Set up a proportion:
- Cross multiply, then divide: 750 × 1 = 750, 750 ÷ 6 = 125
For the second question/part:
- Set up a proportion:
- Cross multiply, then divide: 135 × 1 = 135, 135 ÷ 1.5 = 90
I hope this helps!
Given: Sound Intensity ( I ) =
We know, the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is ⁻¹² W/m².
So, we can say, Reference sound intensity = 10⁻¹² W/m².
We have formula for "sound intensity level LI in dB" when entering sound intensity.
LI = 10×log (I / Io) in dB
Plugging values of I and Io in formula.
LI = 10 × log ()
LI = 10 × log (99000000)
= 10 × 7.99564
LI = 79.96 dB.
Therefore, 79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.