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Ulleksa [173]
3 years ago
11

One year after you buy a tree, it is 8 feet tall. Each year after you buy the tree, it grows 2.25 feet. Write a function that re

presents the
arithmetic sequence. How long does it take for the tree to reach its maximum height of 35 feet?
Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer: 8 + 2.25x = 35

Step-by-step explanation: When you bought the tree it was already 8 feet tall. each year you have it, which is what x represents after putting 2.25 in front of x. it would somehow equal 35. 1st year 2.25 2nd year 4.5 3rd year 6.75 4th year 9 so on and so forth.

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Multiply each term in the parentheses by 3. Your answer is 6a - 12b
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Luis is wrong because 8 to the third power is not 24, but is 512. He multiplied 8 by 3 instead of doing 8x8x8, so Luis made an incorrect claim. 
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Seth's family plans to drive 220 miles to their vacation spot. They would like to complete the drive in 4 hours. Find the averag
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Just divide 220 by 4 to get the answer. So the answer is 55.

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8 0
3 years ago
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kenny6666 [7]

The cost to equip all the stations in the chemistry lab is calculated as: $393.75.

<h3>How to Calculate Total Cost?</h3>

In this scenario, we are given the following:

Total number of stations = 21 stations

Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet

Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet

Cost of 1 rubber tubing = $6.25 per yard

Convert 5 feet to yard:

1 yard = 3 feet

x yard = 5 feet

x = (5 × 1)/3

x = 5/3 feet.

So, the cost of 1 rubber tubing = $6.25 per 5/3

Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5

Cost of total length of tubbing needed = $393.75

Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.

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6 0
2 years ago
The angle 0 lies in Quadrant II . <br>Cos 0 = <br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="TexF
mel-nik [20]

Answer:

\tan(\theta)=\frac{-\sqrt{5}}{2}

Step-by-step explanation:

Since we are in quadrant 2, sine is positive.  Since sine is positive and cosine is negative, then tangent is negative.

Now I'm going to find the sine value of this angle given using one of the Pythagorean Identities, namely \sin^2(\theta)+\cos^2(\theta)=1.

If given \cos(\theta)=\frac{-2}{3}, then we have \sin^2(\theta)+(\frac{-2}{3})^2=1 by substitution of \cos(\theta)=\frac{-2}{3}.

Let's solve:

\sin^2(\theta)+(\frac{-2}{3})^2=1 for \sin(\theta).

\sin^2(\theta)+\frac{4}{9}=1

Subtract 4/9 on both sides:

\sin^2(\theta)=1-\frac{4}{9}

Simplify:

\sin^2(\theta)=\frac{5}{9}

Square root both sides:

\sin(\theta)=\sqrt{\frac{5}{9}}

\sin(\theta)=\frac{\sqrt{5}}{\sqrt{9}}

\sin(\theta)=\frac{\sqrt{5}}{3}

===========

\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}=\frac{\frac{\sqrt{5}}{3}}{\frac{-2}{3}}

Multiplying top and bottom by 3 gives:

\tan(\theta)=\frac{\sqrt{5}}{-2}

I'm going to move the factor of -1 to the top:

\tan(\theta)=\frac{-\sqrt{5}}{2}

7 0
3 years ago
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