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Elena-2011 [213]
3 years ago
8

Dracula jumped 5 times every 30 minutes at that rate, how long,in minutes will it take to jump 6 times?

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

36 minutes

Step-by-step explanation:

If I read this correctly, Dracula jumps 1 time every 6 minutes. If he jumped 5 times in 30 minutes, then that means when he jumped a sixth time, it was 36 minutes that passed since:

30 / 5 = 6

So, if he were to jump a sixth time:

30 + 6 = 36

Therefore, Dracula jumps 1 time per 6 minutes.

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Step-by-step explanation:

cos theta is 2/3 because  cos means reciprocal of sec

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Which represents a quadratic function ?
mars1129 [50]

Answer:

\boxed{\boxed{B.\ f(x)=\dfrac{3}{4}x^2+2x-5}}

Step-by-step explanation:

Quadratic function-

It is a function that can be represented by an equation of the form f = ax^2 + bx + c, where a\neq 0

In a quadratic function, the greatest power of the variable is 2.

As in the first option the highest power is 3, so it is not a quadratic function.

Even though the power of x is 2 in the third option, but as it is in the denominator, so the overall power of x becomes -2. Hence it is not a quadratic function.

As the coefficient of x^2 is 0 in case of fourth option, so it is not a quadratic function.

Equation in option 2 satisfies all the conditions of quadratic function, hence it is the quadratic function.

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4 years ago
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Jessie has a piece of wood that is 8 feet long. He needs to cut pieces that are 7/8 of a foot long. How many pieces will he be a
balandron [24]
8 / (7/8) =
8 * 8/7 =
64/7 =
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3 0
3 years ago
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Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
3 years ago
What’s the answer because I’m confused
Scilla [17]

Answer:

i hate Maths

7 0
3 years ago
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