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ivann1987 [24]
3 years ago
15

Math help please thanks

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0
For most of these questions, all you would have to do is add the angles together and or subtract the larger angle from the smaller one to find the other angle. So in the first case.

You would add the angles, 26 degrees and 60 degrees to find the angle KLM which is about 90 degrees a right angle, in this case it would be 86 degrees.

Similarly, for the other question, take the larger angle, 145 degrees and subtract 61 degrees to solve for the angle that will also add to give 145 degrees,in this case it would be 84 degrees.

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The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is me
Amanda [17]

Answer: 299 m/s

Step-by-step explanation:

The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

v(t) = 6t^2 + 5

Now input 7 in for t to find the velocity.

v(7) = 6(7)^2 + 5

v(7) = 299 m/s

6 0
3 years ago
Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.
Nostrana [21]

Question:

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.

Which statement best describes the relationship between the positions of the two players?

A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.

Answer:

Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

Explanation:

The position of the Dog 1 is (−6, 3).

The position of the Dog 2 is (−6, -3).

From the graph, we can see that the image of Dog 1 is reflected over x-axis. Because to reflect an image over x-axis, the signs of y-coordinate must be changed.

Hence, Option B is correct.

Thus, Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.

7 0
3 years ago
Solve Two Step Eqautions
VashaNatasha [74]
1. n=7
2. w= 7.75 
3. f= -15
4. y = 66
5. g=42
6. p= 2
4 0
3 years ago
Solve for Х.<br> 16<br> 20<br> A 25.6<br> В<br> 6<br> С<br> 12<br> D 15
777dan777 [17]

Answer:

12 which is on C

Step-by-step explanation:

use pathogoras theorem

a^2+b^2=c^2

16^2+b^2=20^2

256+b^2=400

b^2=400-256

b^2=144

b= square root of 144

b= 12

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x-%5Csqrt%7Bx%7D%20-2" id="TexFormula1" title="x-\sqrt{x} -2" alt="x-\sqrt{x} -2" align="absmi
Nata [24]

Answer:

(sqrt(x) +1)(sqrt(x)-2)

Step-by-step explanation:

x - 2 \sqrt{x}  +  \sqrt{x}  - 2 \\  \sqrt{x} ( \sqrt{x}  - 2) + 1( \sqrt{x}  - 2 ) \\ ( \sqrt{x}  + 1)( \sqrt{x}  - 2)

4 0
3 years ago
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