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AveGali [126]
2 years ago
12

I need help with number 4 please you don't need to explain ​

Mathematics
1 answer:
inn [45]2 years ago
8 0
I need some love in my life
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William carefully looked over a _____ before he signed it and moved into his new apartment. warranty lease credit report loan ap
Ber [7]

Answer:

                                                                                                     L

Step-by-step explanation:

3 0
2 years ago
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Which conversion factor would you use to convert from meters to feet?
butalik [34]
<span>1.Take a measurement in feet.
</span>2.Multiply or divide your measurement by a conversion factor.<span> 
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4 0
3 years ago
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The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin
bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, Z_{Critical}=1.645.

We also know that E=5% or E=0.05

Also, since, \hat{p} is not given, we will assume that \hat{p}=0.5. This is because, the formula that we use will have \hat{p}(1-\hat{p}) in the expression and that will be maximum only when \hat{p}=0.5. (For any other value of \hat{p}, we will get a value less than 0.25. For example if, \hat{p} is 0.4, then 1-\hat{p}=0.6 and thus, \hat{p}(1-\hat{p})=0.24.).

We will now use the formula

n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})

We will now substitute all the data that we have and we will get

n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)

n=(32.9)^2\times0.25

n=270.6025

which can approximated to n=271.

So, the brand manager needs a sample size of 271

3 0
3 years ago
You move up 4 units and right 2 units. You end at (-1, 3). Where did you start?
Delicious77 [7]

Answer:

at the begining

Step-by-step explanation:

4 0
3 years ago
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A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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