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3 years ago

Solve for x, will give brainliest

Mathematics

2 answers:

Savatey [412]3 years ago

7 0

Is it 29? i’m not totally sure

Nastasia [14]3 years ago

5 0

Imma guess 29. Hope it’s correct!!

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Rewrite it as a function and isolate Y.

hodyreva [135]

Answer: y= -2x + 12

or f (y ) = 6 - $\frac{y}{2}$

Step-by-step explanation:

just subtract the 2x to get the y alone

8 0

3 years ago

When the British began interfering with American trade and impressing their seamen, what war was declared?

hammer [34]

The Embargo act is all I know for this

5 0

3 years ago

Perform the operation. Enter your answer in scientific notation.<br> 9 x 10^*8 - 5.3 x 10^*8 =

PilotLPTM [1.2K]

Answer:

3.7x10^8

Step-by-step explanation:

did it on calc

3 0

3 years ago

Is 4:12 equivalent to 5:15

vlabodo [156]

Answer:

Yes.

Step-by-step explanation:

Ratios also function as fractions.

4/12 = 1/3 = 0.333

5/15 = 1/3 = 0.333

4 0

2 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

3 years ago