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Valentin [98]
3 years ago
10

Bru this was a challenge......but

Physics
2 answers:
anygoal [31]3 years ago
6 0

Answer:

Free points

Explanation:

S_A_V [24]3 years ago
6 0

Answer:

wdym??

Explanation:?

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How much heat is needed to raise the temperature of 1 kg of iron from 25 degree to 30 degrees?
stiv31 [10]

Answer:300 joules

Explanation:The formula for specific heat is:

E

=

m

c

θ

, where:

E

is the energy needed in joules,

m

is the mass in kilograms,

c

is the specific heat,

θ

is the change in temperature, Celsius of Kelvin doesn't matter.

Here,

m

=

0.125

kg

c

=

480

J/kg

∘

C

θ

=

5

∘

C

, and inputting:

E

=

0.125

⋅

480

⋅

5

E

=

300

J

of energy is needed.

4 0
4 years ago
How do you determine net force
Dima020 [189]
Net force is determined by adding up all of the individual forces on an object. For example, to determine the net force on an airplane, you would add up the lift, weight, thrust, and drag<span>. If forces are in opposite directions, like lift and weight, then you subtract them. During takeoff, the net force on an airplane is forward and up. During landing it is backwards and down.</span>
3 0
3 years ago
Read 2 more answers
What are the conditions required for a rigid body to be in translational equilibrium?
kolezko [41]

Answer:

Explanation:

The condition for translation equilibrium is that is that the net force acting on the body must be zero.

The sum all the external forces acting on the body in horizontal as well as vertical direction must be zero.

∑Fₓ=0  and ∑Fy=0

now if the above two condition are satisfied the rigid body is said to be in  translational equilibrium.

God bless... hope this help to clear your doubt.

5 0
3 years ago
Raina is running for student body president and doesn't want to forget her campaign speech. She practices her speech over and ov
mezya [45]

The answer is intentional.

6 0
4 years ago
Read 2 more answers
A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute =W_B=10 g

Given mass of solvent=W_A=90 g

k_f=1.86^{\circ}C/m

Freezing point of solution =-3.33^{\circ}C

Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}

M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

M_B=62.06 g/mol

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0
3 years ago
Read 2 more answers
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