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lara [203]
3 years ago
14

Which of the following forms of energy must an object have if it is moving at a constant velocity?

Physics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

Kinetic energy

Explanation:

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Find the work done by the force ​F = xyi +(y-x)j over the straight line from​ (-1,1)to (3,-3). The amount of work done is ___?
dalvyx [7]

Answer:

amount of work done isW  =  \frac{-4}{3}      

Explanation:

Formula for work done by force field

W = \int F. dr = \int_{t_o}^{t_1} f(r(t)) r'(t) dt

where

r(t) is parametrization of line

as it is straight line so

r(t) = 1- t) r_o + tr_1   0 \leq t \leq 1

thus,

r(t) = (1-t)(-1,1) + t(3,-3)

    = (-1+t,1-t) + (3t - 3t)

   = (-1+t +3t, 1-t-3t)

r(t) = (4t -1, 1- 4t)

r'(t) = (4,-4)

putting value in above integral

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \int_{0}^{1} (-(4t -1)^2 , 2-8t).(4,-4) dt

                                                  = \int_{0}^{1} (-16 t^2 + 8t -1,2-8t) .(4,-4) dt

                                                  =\int_{0}^{1} (4(-16t^2 +8t -1) -4(2-8t)) dt

                                                   = 4[ -16 \frac{t^3}{3} + 16\frac{t^2}{2} - 3t]_{0}^{1}

\int_{0}^{1} ((4t -1,1-4t)). (4,4) dt = \frac{-4}{3}                                                        

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The gas waste generated by many power plants is
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carbon dioxide

is the answer

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3 years ago
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A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences
Zanzabum

Answer:

1.79 T

Explanation:

Applying,

F = BILsin∅................ Equation 1

Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force

make B the subject of the equation

B = F/ILsin∅............. Equation 2

From the question,

Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)

Substitute these values into equation 2

B = 2.15/(30×0.04×sin90°)

B = 2.15/1.2

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