Answer: Technician B is right.
Explanation:
Evacuation process is used in refrigeration systems to remove moisture, air and non-profit condensable gases in order to achieve maximum function of the system.
vacuum pump is used to draw the sealed AC system into a vacuum. Evacuation of a refrigerant system also helps to maintain pressure, this is so as pulling a vacuum on the system is simply removing matter (mostly air and nitrogen) from inside the system so that the pressure inside drops below atmospheric pressure.
Answer:
very small solid particles called interstellar dust.
Explanation:
In the space between the stars there is gas and dust, which represent at least 20% of the mass of our galaxy. In the Milky Way it is considered that there is a gas density of approximately 0.2 to 0.5 atoms / cm3 in the surroundings of the Sun; with respect to the dust an average of 1 g / cm3 is estimated.
Gas is about atoms and molecules, mainly hydrogen; In order of abundance, helium, carbon, oxygen, nitrogen and iron follow. On the other hand, the dust is tiny particles, generally smaller than 10 microns; the dust does not shine and therefore it is only distinguished when it is projected on bright regions (nebulae or clusters).
Interstellar matter is mainly concentrated towards the plane of the galaxy, in the strip corresponding to the Milky Way; there you can see bright nebulas of diffuse character called nebulas. These nebulae are classified according to three types: (a) bright or emission nebulae, (b) reflection nebulae and (c) planetary nebulae.
Hydrogen appears both ionized and neutral; The bright nebulae are composed of ionized hydrogen and other ionized elements. Non-ionized (neutral) hydrogen is found in the spiral arms of the Milky Way and can be detected through radio waves.
when approaching the front of an idling jet engine, the hazard area extends forward of the engine approximately 25 feet.
<h3>What impact, if any, would jet fuel and aviation gasoline have on a turbine engine?</h3>
Tetraethyl lead, which is present in gasoline, deposits itself on the turbine blades. Because jet fuel has a higher viscosity than aviation gasoline, it may retain impurities with greater ease.
Once the gasoline charge has been cleared, start the engine manually or with an electric starter while cutting the ignition and using the maximum throttle.
On the final approach, the aeroplane needs to be re-trimmed to account for the altered aerodynamic forces. A substantial nose-down tendency results from the airflow producing less lift on the wings and less downward force on the horizontal stabiliser due to the reduced power and slower velocity.
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Answer:

Explanation:
From the conservation of mechanical energy




Solve to velocity v2




<h3><u>Given</u> :</h3>
Three identical resistors of resistances 5Ω, 10Ω and 30Ω are connected with a battery of 12V
<h3><u>To Find</u> :</h3>
We have to find current through the each resistor and equivalent resistance of circuit
<h3><u>SoluTion</u> :</h3>
➝ Equivalent resistance of series connection is given by
➝ We know that, Equal current flow through each resistor in series connection.
➝ As per ohm's law, Current flow through a conductor is directly proportional to the applied potential difference.
◈ <u>Equivalent resistance</u> :
⇒ Req = R1 + R2 + R3
⇒ Req = 5 + 10 + 30
⇒ <u>Req = 45Ω</u>
◈ <u>Current flow in circuit</u> :
⇒ V = IReq
⇒ 12 = I × 45
⇒ <u>I = 0.27A</u>
፨ Therefore, 0.27A current will flow through each resistor.