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2 years ago

I’m sorry, but the person you are calling has a voice mailbox that has not been set up yet.

Physics

2 answers:

Alisiya [41]2 years ago

7 0

Answer: Or please call again to see if they reached the phone yet.

Explanation: It always stops ringing right before someone gets to there phone so call again in 2 minutes. :3

ladessa [460]2 years ago

5 0

Answer:

bye bye

Explanation:

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Physics Conversion help!!

stiv31 [10]

[Assuming that you've written 3.40 kg in 'a', and not 3.90 kg]

(a) 3,400 g x <u>0.001</u> = 3.40 kg [converting grams to kilograms]

(b) 220 cm x <u>0.01</u> = <u>2.2</u> m [converting centimeters to meters]

(d) 6.53 m x <u>100</u> = <u>653</u> cm [converting meters to centimeters]

5 0

4 years ago

A 950-kg car strikes a huge spring at a speed of 22m/s (fig. 11-54), compressing the spring 5.0m. (a) what is the spring stiffne

alukav5142 [94]

(a) The spring stiffness constant of the spring is 18,392 N/m.

(b) The time the car was in contact with the spring before it bounces off in the opposite direction is 0.23 s.

<h3>Kinetic energy of the car</h3>

The kinetic energy of the car is calculated as follows;

K.E = ¹/₂mv²

K.E = ¹/₂ x 950 x 22²

K.E = 229,900 J

<h3>Stiffness constant of the spring</h3>

The stiffness constant of the spring is calculated as follows;

K.E = U = ¹/₂kx²

k = 2U/x²

k = (2 x 229,900)/(5)²

k = 18,392 N/m

<h3>Force exerted on the spring</h3>

F = kx

F = 18,392 x 5

F = 91,960 N

<h3>Time of impact</h3>

F = mv/t

t = mv/F

t = (950 x 22)/(91960)

t = 0.23 s

Learn more about spring constant here: brainly.com/question/1968517

#SPJ4

3 0

2 years ago

kristine speeds past a parked police car at 32 m/s. The police car starts from rest with a uniform acceleration of 2.5 m/s^2. Ho

Digiron [165]

$32 = 0 \times t + \frac{1}{2} \times 2.5 \times t^{2} \\ 32 = 0 + 1.25 \times t {}^{2} \\ 32 = 1.25t {}^{2} \\ \frac{32}{1.25} = \frac{1.25t {}^{2} }{1.25} \\ t {}^{2} = 25.6 \\ \sqrt{t {}^{2} } = \sqrt{25.6} \\ t = 5.1seconds \\$

7 0

3 years ago

If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle

soldi70 [24.7K]

Answer:

The angle that the wave would be $\theta = sin ^{-1}\frac{2 \lambda}{D}$

Explanation:

From the question we are told that the opening to the harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the on at angle greater than the diffraction first minimum would be slightly affected

The minimum is as a result of destructive interference

And for single-slit this is mathematically represented as

$D sin \ \theta =m \lambda$

where D is the slit with

$\theta$ is the angle relative to the original direction of the wave

m is the order of the minimum j

$\lambda$ is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

And the both is safe at the angle equal to the second minimum then

The the angle is evaluated as

$\theta = sin ^{-1}[\frac{m\lambda}{D} ]$

Since for second minimum m= 2

The equation becomes

$\theta = \frac{2 \lambda}{D}$

3 0

3 years ago

What is the direction of the field halfway between two horizontal parallel wires if the top wire has a current of 4 A to the lef

Alex777 [14]

Answer:

A) Out of the page.

Explanation:

Right-hand rule points the direction of the magnetic field at any point.

<u>Top wire</u>: Current is to the left. Point your thumb to the left and curl your other fingers around the wire. The tips of the four fingers points the direction of the field at that point. In this case, out of the page.

<u>Bottom wire</u>: Current is to the right. Point your thumb to the right and curl your other fingers around the wire. The tips of the four finger points out of the page again.

So, the total field produced by both wires is directed out of the page.

Another method to figure out the direction is the mathematical method.

Use the B-field formula:

$d\vec{B} = \frac{\mu_0}{4\pi}\frac{Id\vec{l}\times \^r}{r^2}$

The cross product between the direction of the current and the target position gives the direction of the B-field. If the left is -x direction and downwards is the -y direction, then

$(-\^x) \times (-\^y) = +\^z$ for the top wire.

$(+\^x) \times (+\^y) = +\^z$ for the bottom wire.

4 0

3 years ago