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2 years ago

What is 3 times 1/3 and subtract 5

Mathematics

2 answers:

lukranit [14]2 years ago

7 0

3* ( 1/3 -5)= -14 hope this helps

riadik2000 [5.3K]2 years ago

5 0

Answer: -4

Step-by-step explanation:

Rephrase the given expression

3 times 1/3 and subtract 5

3×1/3-5

Do multiplication first, then subtraction

3×1/3-5

=3/3-5

=1-5

=-4

Hope this helps!! :)

Please let me know if you have any questions

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Which of the following tables shows the correct steps to transform x^2+6x + 8=0

Vlad1618 [11]

Perhaps the most concise way to factor is by "completing the square" which is how the quadratic formula is derived...

x^2+6x+8=0 move constant to other side, subtract 8 from both sides

x^2+6x=-8, halve the linear coefficient, square it, then add that to both sides, in this case (6/2)^2=3^2=9

x^2+6x+9=1 now the left side is a perfect square of the form

(x+3)^2=1 take the square root of both sides

x+3=±√1 subtract 3 from both sides

x=-3±√1

x=-3±1

x=-4 and -2

Since the zeros occur when x=-4 and -2 the factors of the equation are:

(x+2)(x+4)

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3 years ago

Use synthetic division to solve (x4 – 1) ÷ (x – 1). What is the quotient?

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Answer:

Simplify, x(3) + x(2) + x + 1

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Help me asap please & thank you.

vaieri [72.5K]

Howwwww.....................

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3 years ago

Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)

Anna71 [15]

GIVEN:

$5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)$

remember:

$\sqrt{u} = {u}^{ \frac{1}{2} }$

And

${u}^{n} \times {u}^{m} = {u}^{n + m}$

SOLVE:

start by multiplying the factors:

$5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))$

simplify by combing like terms. Most terms subtract off, leaving:

$5( {u}^{6} - 1)$

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

$5( {u}^{3} - 1)( {u}^{3} + 1)$

I'm not exactly sure what form they want the answer in...

so taking the square root:

$\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }$

so my best answer is:

${5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }$
or the more factored form:

${5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }$

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!

7 0

3 years ago