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Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find the equation of the line with the given description: horizontal, passes through (0,11).

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4 years ago

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Vanyuwa [196]

Answer:

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Step-by-step explanation:

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3 years ago

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How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!

Hitman42 [59]

The $i$ in the denominator is missing in the second expression. It should be

$\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

This follows from

$e^{iat}=\cos at+i\sin at$
$e^{-iat}=\cos at-i\sin at$
$\implies e^{iat}-e^{-iat}=2i\sin at$
$\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

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4 years ago

The gcf of 14 and 22

Finger [1]

The GCF is 2
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3 years ago

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Find the vertical and horizontal asympotote for (×-2) (×+3)/ (2×+2)

nekit [7.7K]

$\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1$

when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.

quick note:

when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.

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3 years ago