Is it greater than, equal to, or less than

Find the equation of a line that passes through the given points (-6,-5) and (6,-13)

NeTakaya

Answer:

y+5=-3/4(x+6)

or in slope intercept

y= -3/4x-38/4

Step-by-step explanation:

To write the equation of a line we must have a slope and a point. To find the slope we use the slope formula and substitute (x,y) points in it as shown below:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5--13}{-6-6}=\frac{-5+13}{-6+-6}=\frac{8}{-12}=\frac{-3}{4}$

Now that we have the slope, plug in the slope and choose one point to plug into the point slope formula. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--5)=-3/4(x--6)

y+5=-3/4(x+6)

y+5=-3/4x-18/4

y=-3/4x-18/4-20/4

y= -3/4x-38/4

5 0

3 years ago

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So, you go to a Coffee Shop. They have either small, medium or large coffee. They have vanilla or hazelnut flavor. What are the

Talja [164]

Answer:

6

Step-by-step explanation:

Size times flavor. 3 times 2 = 6

6 0

2 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

NO SOLUTION

7 0

2 years ago

The triangle on the right is scaled copy of the triangle on the left identified the scale factor

Lilit [14]

Answer:

is there supposed to be a picture with it? i can't solve it without more information. sorry

3 0

3 years ago

What is the answer 5a - 3 = 8a + 6

earnstyle [38]

Subtract 5a from both sides

-3=3a+6

Subtract 6 from both sides

-9=3a

Divide by three

a= -9/3 (which is -3)

Remember what you do to one side you must do to the other

7 0

2 years ago

Read 2 more answers