-4 is the x intercept.as in the values on the x-axis
If the 5 scores have a mean of 8, then their total sum would be 8*5 = 40
Now if one score if added (let's call this score x), there are 6 scores and the mean changes to 9, thus:
(40 + x)/6 = 9
40 + x = 54
x = 14
Total no. of births = 2000
Births of girls = 64
Birth% of girls




Hence, the number of girls are significantly low.
Answer:

Step-by-step explanation:
-We can use the exponential decay function to estimate the size after 13 years:

Where:
is the size after t years, t is the time, r is the rate of decay and
the original size.
#We substitute and calculate as:

Hence, the forest covers
after 13 years.