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3 years ago

If u answer ill give brainlist

Mathematics

1 answer:

makkiz [27]3 years ago

3 0

Answer:

120; 643 units squared

Step-by-step explanation:

Perimeter: Add all the sides, so 120 units

_________________________________

Area: First multiply 19 by 24 for the first shape within this other shape, so That equals 456 units squared. Since we know that one whole side is 36 we can subtract 19 from it to get the lower side of the smaller shape and then multiply that by 11. So the smaller side ends up being 17. So 17 times 11 equals: 187 units squared. Then just add the areas together 187+456=643 units squared.

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25+12 1/2 + 61/4+31/8+19/16+25/32=

Len [333]

Make them all have the same denominator
32

25+12 16/32+488/32+124/32+38/32+25/32

Add all of the numerators... to get 691/32+1184/32
1875/32
Simplify to get 58 19/32

4 0

3 years ago

Independent Practice

mariarad [96]

Answer:

B. (1, 0)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Equations<br> Solve T = C(9+ AB) for B

MaRussiya [10]

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

6 0

2 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

3 years ago

I need help with C please.

zlopas [31]

9514 1404 393

Answer:

║w║ = 6

Step-by-step explanation:

(c) The magnitude of w is computed the same way the magnitudes of the other vectors are computed. It is the root of the sum of the squares of the components.

║w║= ║<-6, 0>║ = √((-6)² +0²) = √36

║w║= 6

4 0

3 years ago