1. This is a nonagon. A nonagon is a 9-sided polygon; the figure has 9 sides.
2. This is not a regular polygon. A regular polygon is equiangular and equilateral which means that all of the angles are equal in measure and all of the sides are equal in length. The figure shown does not have equal sides or angles; therefore, it is an irregular polygon.
For this case, the first thing you should do is define a variable.
We have then:
t: temperature (degree Fahrenheit).
We write then the inequation that adapts to the problem:
t> = 451
Answer:
an inequality that is true only for temperatures at which books spontaneously catch on fire is:
t> = 451
7/3 written as a mixed fraction is 2 1/3
So
7/3 = 2 1/3
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Given:
Capacity of jet plane = 200,000 liters of fuel
Fuel used during flight = 130,000 liters
To find:
The percentage of the fuel capacity it uses on this flight.
Solution:
According to the question, we need to find 130,000 is what percent of 200,000.



Therefore, the jet plane uses 65 percent of fuel capacity during flight.