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3 years ago

Find cotθ if tanθ = 2 and 180° < θ < 270° Plz help

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

1/2

Step-by-step explanation:

cotangent is the reciprocal of a tangent

tanθ = 2

cotθ = 1/2

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This graph shows a proportional relationship.

Nonamiya [84]

Not quite sure but:
2/3 = 3/4
divide all by 2/3 to get a 1 value so
1 = 0.8

4 0

3 years ago

Read 2 more answers

What is the area of the green shaded part?

Mandarinka [93]

Answer:

$7.74 \: {cm}^{2}$

Step-by-step explanation:

Area of the green shaded part

= Area of square with side 6 cm - Area of circle with radius (6/2=3) 3 cm.

$= {side}^{2} - \pi {r}^{2} \\ = {6}^{2} - 3.14 \times {3}^{2} \\ = 36 - 28.26 \\ = 7.74 \: {cm}^{2}$

8 0

3 years ago

Simplify this expression: 16+28/2-6/10-4x2

almond37 [142]

Answer:

Your answer would be -4x^2+147/5

3 0

4 years ago

What is the slant height x of this square pyramid?

Inessa05 [86]

1) What is the slant height x of this square pyramid? Express your answer in radical form

sin 60=x/4--------> x=4*sin 60------> 4*(√3/2)-------> 2 √3 m

the answer Part 1) is 2 √3 m

2) The base of a regular pyramid is a hexagon. What is the area of the base of the pyramid?
[area of the base}=[area of hexagon]
[area of hexagon]=6*[area of triangle]

area of triangle
sin 60=a/14-------> a=(√3/2)*14-------> a=7√3 cm
cos 60=(b/2)/14--------> (b/2)=cos 60*14-----> (1/2)*14---------> (b/2)=7
base of triangle=2*7--------> b=14 cm

[area of triangle]=14*7√3 /2--------> 49√3 cm²
so
[area of hexagon]=6*[49√3]--------> 294√3 cm²

7 0

3 years ago

The number of fatalities due to car crashes, based on the number of miles driven, begins to climb after the driver is past age 6

andriy [413]

Answer:

The fataly rate per 100 million vehicle miles driven is approximately for average driver in the 50-54 age group is 0.7.

The fataly rate per 100 million vehicle miles driven is approximately for average driver in the 60-64 age group is 3.3268.

Step-by-step explanation:

The number of fatalities per 100 million vehicle miles driven is approximately given by the following function:

$N(x) = 0.3336x^{3} - 0.118x^{2} + 0.215x + 0.7$

In which x corresponds to the age group.

What is the fatality rate per 100 million vehicle miles driven for an average driver in the 50-54 age group?

This is N(0), since $x = 0$ represents those aged 50-54.

So:

$N(x) = 0.3336x^{3} - 0.118x^{2} + 0.215x + 0.7$

$N(0) = 0.7$

The fataly rate per 100 million vehicle miles driven is approximately for average driver in the 50-54 age group is 0.7.

In the 60-64 age group?

This is N(2), since $x = 2$ represents those aged 60-64.

$N(x) = 0.3336x^{3} - 0.118x^{2} + 0.215x + 0.7$

$N(2) = 0.3336*2^{3} - 0.118*2^{2} + 0.215(2) + 0.7 = 3.3268$

The fataly rate per 100 million vehicle miles driven is approximately for average driver in the 60-64 age group is 3.3268.

3 0

3 years ago

Find ﻿cotθ if ﻿tanθ = 2 and ﻿180° < θ < 270° Plz help

Find cotθ if tanθ = 2 and 180° < θ < 270° Plz help