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2 years ago

Find cotθ if tanθ = 2 and 180° < θ < 270° Plz help

Mathematics

1 answer:

Musya8 [376]2 years ago

6 0

Answer:

1/2

Step-by-step explanation:

cotangent is the reciprocal of a tangent

tanθ = 2

cotθ = 1/2

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K= 1/2mv^2<br> Solve for V

jeyben [28]

Hi there!

v = ± $\sqrt{\frac{2K}{m} }$

- - - - - - - - -

K = 1/2mv²

Isolate for the variable "v". We can begin by dividing both sides by 1/2. (Multiply by the reciprocal, or 2):

2 · K = 2 · (1/2mv²)

2K = mv²

Continue isolating by dividing both sides by "m":

2K / m = v²

Take the square root of both sides. Remember that the solution can either be positive or negative since there are positive and negative roots.

v = ± $\sqrt{\frac{2K}{m} }$

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$\frac{1}{2}$ x+13=9
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Answer:

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2 years ago

Find ﻿cotθ if ﻿tanθ = 2 and ﻿180° < θ < 270° Plz help

Find cotθ if tanθ = 2 and 180° < θ < 270° Plz help