<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>
Carbon discovered in Prehistoric times.. Discoverer will probably never be known
<span><em><u>Climatology </u>is a <u>subspecialty </u>of a </em><u><em>Climate</em></u><em> and for how the <u>climate</u> changes. This is averaged out from over a set of a period of time.
<u>I hope this helps! ;D</u></em></span>
The empirical formula is K₂O.
The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.
The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.
So, our job is to calculate the <em>molar ratio</em> of K to O.
Step 1. Calculate the <em>moles of each element
</em>
Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K
Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0
Step 2. Calculate the <em>molar ratio of each elemen</em>t
Divide each number by the smallest number of moles and round off to an integer
K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1
Step 3: Write the <em>empirical formula
</em>
EF = K₂O
