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MatroZZZ [7]
3 years ago
8

1. What is the oxidation number for the silver ion in tarnish?

Chemistry
1 answer:
spayn [35]3 years ago
7 0
Tarnish is Ag2S-silver sulfide and the oxidation state of silver is +1
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Explanation :

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\ln k=-\frac{Ea}{RT}+\ln A             ............(1)

where,

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Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:

\ln (2.95\times 10^{-3}L/mol.s)=-\frac{Ea}{8.314J/K.mol\times 435K}+\ln (3.00\times 10^{10}L/mol.s)

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