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MatroZZZ [7]
3 years ago
8

1. What is the oxidation number for the silver ion in tarnish?

Chemistry
1 answer:
spayn [35]3 years ago
7 0
Tarnish is Ag2S-silver sulfide and the oxidation state of silver is +1
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How was potassium discovered?​
BaLLatris [955]

Answer:

Potassium was the first metal to be isolated by electrolysis. It was discovered by the  English chemist Sir Humphry Davy by decomposing molten potassium hydroxide (KOH) with a voltaic battery.

Explanation:

6 0
3 years ago
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Carbon dioxide gas is produced by the reaction of oxygen gas and solid carbon . Write a balanced chemical equation for this reac
grandymaker [24]

I think it’s like this.

C+2O→CO2

5 0
4 years ago
What is the concentration in milligrams per milliter of a solution containing 23.5 meq sodium chlorise per milliliter? mw nacl =
ValentinkaMS [17]

1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.

Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.

It is calculated in mg/ml.

The unit of measurement frequently used for electrolytes is the milliequivalent (mEq). This value compares an element's chemical activity, or combining power, to that of 1 mg of hydrogen.

Formula for calculating concentration in mg/ml is

Conc. (mg/ml) = M(eq) /ml ×  Molecular weight / Valency

Given

M(eq) NaCl/ ml = 23.5

Molecular weight pf NaCl = 58.5 g/mol

Valency = 1

Putting the values into the formula

Conc. (mg/ml) = 23.5 ×58.5/1

                       = 1374.75 mg/ml

Hence, 1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.

Learn more about Concentration here brainly.com/question/14500335

#SPJ4

7 0
2 years ago
Wich stament describes to organ systems working together to get rid of waste played by cells
IceJOKER [234]

Answer:

C. Kidneys filter wastes from the bloodstream and produce urine

Explanation:

5 0
3 years ago
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Calculate δg∘rxn and e∘cell for a redox reaction with n = 3 that has an equilibrium constant of k = 4.4×10−2. you may want to re
lapo4ka [179]
a) First, to get ΔG°rxn we have to use this formula when:

ΔG° = - RT ㏑ K 

when ΔG° is Gibbs free energy 

and R is the constant = 8.314 J/mol K

and T is the temperature in Kelvin = 25 °C+ 273 =  298 K 

and when K = 4.4 x 10^-2

so, by substitution:

ΔG°= - 8.314 * 298 *㏑(4.4 x 10^-2)

      = -7739 J  = -7.7 KJ


b) then, to get E
° cell for a redox reaction we have to use this formula:

ΔE° Cell = (RT / nF) ㏑K

when R is a constant = 8.314 J/molK

and T is the temperature in Kelvin = 25°C + 273 = 298 K

and n = no.of moles of e- from the balanced redox reaction= 3

and F is Faraday constant = 96485 C/mol

and K = 4.4 x 10^-2

so, by substitution:

∴ ΔE° cell = (8.314 * 298 / 3* 96485) *㏑(4.4 x 10^-2)

              = - 2.7 x 10^-2 V
  
8 0
3 years ago
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