Find lim (2-y)^7/3 y-> -6

Mathematics

1 answer:

7nadin3 [17]2 years ago

6 0

Answer:

128

Step-by-step explanation:

if to substitute y= -6, then

$\lim_{y \to \ {-6}} \sqrt[3]{(2-y)^7}=\sqrt[3]{8^7}=2^7=128.$

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