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lukranit [14]
3 years ago
12

A bowling ball has a diameter of 8.5 inches. What is its approximate volume?

Mathematics
2 answers:
Alex Ar [27]3 years ago
6 0

Answer:

321.56

Step-by-step explanation:

volume = (4/3) * π * r³

vodomira [7]3 years ago
3 0

Answer:

volume=321.56inch^3

diameter=8.5

radius=4.25

volume=4/3πr^3

volume=4/3π(4.25)^3

volume=321.56inch^3

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Complex roots occur when b^2 - 4ac is negative.

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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviat
nexus9112 [7]

Answer:

Two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

Step-by-step explanation:

We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviation of 0.07 millimeters.

<em>Let X = diameters of bolts produced in a machine shop</em>

So, X ~ N(\mu=5.65,\sigma^{2} = 0.07^{2})

The z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

<u>Now, we have to find the two diameters that separate the top 4% and the bottom 4%.</u>

  • Firstly, Probability that the diameter separate the top 4% is given by;

        P(X > x) = 0.04

        P( \frac{X-\mu}{\sigma} > \frac{x-5.65}{0.07} ) = 0.04

        P(Z > \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the top 4% is given as 1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = 1.7507

              x-5.65 = 0.07 \times 1.7507

                         x = 5.65 + 0.122549 = 5.77

  • Secondly, Probability that the diameter separate the bottom 4% is given by;

        P(X < x) = 0.04

        P( \frac{X-\mu}{\sigma} < \frac{x-5.65}{0.07} ) = 0.04

        P(Z < \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the bottom 4% is given as -1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = -1.7507

              x-5.65 = 0.07 \times (-1.7507)

                         x = 5.65 - 0.122549 = 5.53

Therefore, the two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

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Find the area of this parallelogram. 12 inches 6 in. 7 in. ​
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area of this parallelogram=b×h=13×6=72inches

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