Answer:
a. 3,392.7 N
b. 3,392.7 N
Explanation:
We are given the following information;
- Mass of the truck as 1052 kg
- initial speed as 0 m/s
- Final speed as 20.0 m/s
- Time taken as 6.20 s
#a. We are required to calculate the acceleration;
We need to know the formula of getting acceleration;
a = (v-u)/t
Where v is the final velocity, u is the initial velocity
Therefore;
a = (20 m/s - 0 m/s)/6.20s
= 3.225 m/s²
Thus, the average acceleration of the truck is 3.225 m/s²
#b. We are required to calculate the net force on the truck
We need to know that;
According to the second Newton's law of motion, F=ma
Where F is the net force, m is the mass and a is the acceleration.
Therefore;
Net force, F = mass × Acceleration
= 1052 kg × 3.225 m/s²
= 3,392.7 N
Thus, the net force on the truck is 3,392.7 N
The answer would be A transverse
Answer:
Force = 3481.1 N.
Explanation:
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