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3 years ago

If there are 745 watts for every horsepower, how many horses would it take to power a single hundred-watt light bulb?

Physics

2 answers:

sattari [20]3 years ago

6 0

0.14 (rounded to the nearest hundreth)(full answer: 0.13544323097)

liraira [26]3 years ago

6 0

Answer:

The horse power is 0.1340 hp.

Explanation:

Given that,

Horse power = 745 watts

One horsepower is about 745 watts.

Since the bulb consume 100 watt of power

We need to calculate the horse power

$P_{hp}=\dfrac{P_{w}}{745}$

$P_{hp}=\dfrac{100}{745}$

$P_{hp}=0.1342\ hp$

Hence, The horse power is 0.1342 hp.

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3 years ago

Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down th

vladimir2022 [97]

Answer:

The distance is 300 m.

Explanation:

Given that,

Time = 30 s

Speed = 80 m/s

Distance = 1200 m

Speed of smaller plane = 40 m/s

We need to calculate the acceleration

Using equation of motion

$s= ut+\dfrac{1}{2}at62$

Put the value in the equation

$1200=0+\dfrac{1}{2}\times a\times(30)^2$

$a=\dfrac{2\times1200}{30\times30}$

$a=2.67\ m/s^2$

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Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$40^2=0+2\times2.67\times s$

$s=\dfrac{40^2}{2\times2.67}$

$s=299.62\approx 300\ m$

Hence, The distance is 300 m.

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3 years ago

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3 years ago

Read 2 more answers

You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land.

Alika [10]

Answer:

d = 2021.6 km

Explanation:

We can solve this distance exercise with vectors, the easiest method s to find the components of the position of each plane and then use the Pythagorean theorem to find distance between them

Airplane 1

Height y₁ = 800m

Angle θ = 25°

cos 25 = x / r

sin 25 = z / r

x₁ = r cos 20

z₁ = r sin 25

x₁ = 18 103 cos 25 = 16,314 103 m = 16314 m

z₁ = 18 103 sin 25 = 7,607 103 m= 7607 m

2 plane

Height y₂ = 1100 m

Angle θ = 20°