Question

Please help me people

Answer 1

Answer :

(1) The density of asphalt is, $1200kg/m^3$

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

Part 1 :

As we are given:

Mass of block = 90 kg

Volume of block = $0.075m^3$

Formula used :

$\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}$

Now put all the given values in this formula, we get:

$\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3$

Thus, the density of asphalt is, $1200kg/m^3$

Part 2(a) :

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

Part 2(b) :

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

$\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}$

$2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}$

$\text{Mass of aluminium}=15.59kg$

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Answer 2

Answer:

1 ) density = 1200[kg/m^3]

2)

a) wide = 0.35[m]

long = 1,1 [m]

thick  = 0.015 [m]

b)

Volume = 0.005775[m^3]

mass = 15.6 [kg]

Explanation:

1)

This problem can be solved by knowing the definition of density which is expressed as the relation between mass and volume, so that the following equation can give us the density value.

$density=\frac{m}{V}\\ where:\\m= mass [kg]\\V= volume [m^3]\\replacing\\density=\frac{90}{0.075} \\density=1200 [kg/m^3]$

2)

The following data is equal to:

a)

wide = 35 [cm] = 0.35[m]

long = 11 [dm] = 11 [decimeters] = 1,1 [m]

thick = 15 [mm] = 0.015 [m]

b)

We know that density is the relationship between mass and volume of a body.

So the volume will be:

volume = wide * long * thick = (0.35*1.1*0.0015) = 0.005775[m^3]

$the mass will be:\\m=density*volume\\m=2700[kg/m^3]*0.005775[m^3]\\m=15.6[kg]$