Both A and D are negative products.
Answer:

Step-by-step explanation:
The distance formula states that the distance between two points
and
is
.
The two points we have are
and
. Plugging these numbers into the distance formula, we have
.
Simplifying with order of operations, first using the distributive property, gives
.
Squaring and adding gives

which is the answer in simplest form. This also rounds to about 12.04.
Answer:28.6
I started by seeing how many 2.4 can go into 68.64. I found that it is pretty easy to find that if you multiply the 2.4 by ten you get 24 so we do that twice and have 48. We then subtract 48 from the 68.64 which leaves us with 20.64. If we multiply 2.4 by 5 we get 12 so once again subtract 12 from that 20.64 and now we are left with 8.64. So now we need to figure out how many more 2.4 are left well it is more than three because three gives us 7.2 so let’s subtract that from it now we are left with 1.44. Now we need to find out what times 2.4 gives us 1.44. Well it would be .6. So now if we add up everything we get the answer of 28.6. Sorry if this very complicated
Answer:
Radius =6.518 feet
Height = 26.074 feet
Step-by-step explanation:
The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder
Volume of a Hemisphere 
Volume of a Cylinder 
Therefore:
The Volume of the Solid formed

Area of the Hemisphere =
Curved Surface Area of the Cylinder =
Total Surface Area=

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.
Therefore total Cost, C

Recall: 
Therefore:

The minimum cost occurs at the point where the derivative equals zero.


![-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518](https://tex.z-dn.net/?f=-27840%2B32%5Cpi%20r%5E3%3D0%5C%5C27840%3D32%5Cpi%20r%5E3%5C%5Cr%5E3%3D27840%20%5Cdiv%2032%5Cpi%3D276.9296%5C%5Cr%3D%5Csqrt%5B3%5D%7B276.9296%7D%20%3D6.518)
Recall:

Therefore, the dimensions that will minimize the cost are:
Radius =6.518 feet
Height = 26.074 feet
<span>a regular hexagon inscribed in a circle </span>