Answer:
y=2x-5 and y=3-2x
Step-by-step explanation:
The first one is X, then the second one would be X+1 ( adding one, makes it consecutive).
Now you have X + X+1 = 667
Simplify:
2x +1 = 667
Subtract 1 from each side:
2x = 666
Divide both sides by 2:
x = 666 /2
x = 333
The first marker is 333
The second marker = 333 +1 = 334
Complete Question:
Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ? For what values?(Make sure to use an inequality)
Answer:
y < 3
Step-by-step explanation:
The given two fractions are:
and ![\frac{3y-7}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B3y-7%7D%7B12%7D)
We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:
![\frac{7-2y}{6} >\frac{3y-7}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B7-2y%7D%7B6%7D%20%3E%5Cfrac%7B3y-7%7D%7B12%7D)
The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.
Multiplying both sides of inequality by 12, we get:
![12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\ 2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y](https://tex.z-dn.net/?f=12%20%5Ctimes%20%5Cfrac%7B7-2y%7D%7B6%7D%20%3E%2012%20%5Ctimes%20%5Cfrac%7B3y-7%7D%7B12%7D%20%5C%5C%5C%5C%20%202%287-2y%29%3E3y-7%5C%5C%5C%5C%2014-4y%3E3y-7%5C%5C%5C%5C%2014%2B7%3E3y%2B4y%5C%5C%5C%5C%2021%3E7y%5C%5C%5C%5C%203%3Ey%5C%5C%5C%5C%20y%3C3)
This means, for y lesser than 3, the value of first fraction is larger than the second one.
The area of a circle is the number of square units inside that circle. If each square in the circle to the left has an area of 1 cm2<span>, you could count the total number of squares to get the area of this circle. Thus, if there were a total of 28.26 squares</span>
Answer:
h(n) = - 5.3![(-11)^{n-1}](https://tex.z-dn.net/?f=%28-11%29%5E%7Bn-1%7D)
Step-by-step explanation:
This is a geometric sequence with n th term
h(n) = h(1) ![(r)^{n-1}](https://tex.z-dn.net/?f=%28r%29%5E%7Bn-1%7D)
where h(1) is the first term and r the common ratio
Here h(1) = - 5.3 and r = - 11, thus
h(n) = - 5.3
← explicit formula