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Ivenika [448]
3 years ago
9

What is the best way to increase the solubility of something?

Physics
2 answers:
Svetllana [295]3 years ago
4 0
INCREASE THE TEMPERATURE

Scrat [10]3 years ago
4 0

Answer: To increase the temperature

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A 50-kg cart is on an incline of 30 degrees above the horizontal. The cart is at rest. The static coefficient of the slope is 0.
sesenic [268]

The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude <em>w</em>), the normal force (mag. <em>n</em>), and the friction force (maximum mag. <em>f</em> ).

In the horizontal direction, we have

<em>n</em> cos(120º) + <em>f</em> cos(30º) = 0

-1/2 <em>n</em> + √3/2 <em>f</em> = 0

<em>n</em> = √3 <em>f</em>

and in the vertical,

<em>n</em> sin(120º) + <em>f</em> sin(30º) + (-<em>w</em>) = 0

<em>n</em> sin(120º) + <em>f</em> sin(30º) = (50 kg) (9.80 m/s²)

√3/2 <em>n</em> + 1/2 <em>f</em> = 490 N

Substitute <em>n</em> = √3 <em>f</em> and solve for <em>f</em> :

√3/2 (√3 <em>f </em>) + 1/2 <em>f</em> = 490 N

2 <em>f</em> = 490 N

<em>f</em> = 245 N

(pointed up the incline)

4 0
3 years ago
When a hammer thrower releases her ball, she is aiming to maximize the distance from the starting ring. Assume she releases the
Taya2010 [7]

Answer:

The angular velocity is 15.37 rad/s

Solution:

As per the question:

\theta = 54.6^{\circ}

Horizontal distance, x = 30.1 m

Distance of the ball from the rotation axis is its radius, R = 1.15 m

Now,

To calculate the angular velocity:

Linear velocity, v = \sqrt{\frac{gx}{sin2\theta}}

v = \sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}

v = \sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}

v = \sqrt{\frac{294.98}{sin109.2^{\circ}}} = 17.67\ m/s

Now,

The angular velocity can be calculated as:

v = \omega R

Thus

\omega = \frac{v}{R} = \frac{17.67}{1.15} = 15.37\ rad/s

8 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
Tema [17]

Answer:

841.5 Hz

Explanation:

Given

y = 50 cm = 0.5 m

d = 5.00 m

L = 12.0 m away from the wall

v = speed of sound = 343 m/s

The image of the scenario is presented in the attached image.

When destructive interference is being experienced from 50 cm (0.5 m) parallel to the wall, the path difference between the distance of the two speakers from the observer is equal to half of the wavelength of the wave.

Let the distance from speaker one to the observer's new position be d₁

And the distance from the speaker two to the observer's new position be d₂

(λ/2) = |d₁ - d₂|

d₁ = √(12² + 3²) = 12.3693 m

d₂ = √(12² + 2²) = 12.1655 m

|d₁ - d₂| = 0.2038 m

(λ/2) = |d₁ - d₂| = 0.2038

λ = 0.4076 m

For waves, the velocity (v), frequency (f) and wavelength (λ) are related thus

v = fλ

f = (v/λ) = (343/0.4076) = 841.5 Hz

Hope this Helps!!!

7 0
4 years ago
Read 2 more answers
If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.
egoroff_w [7]

Answer:

Explanation:

given :-

force applied = 117.6N

Area = 20 m^2

Pressure =?

solution:-

Pressure = Force / Area

= 117.6 N / 20 m^2

= 5.88 Pascals

Hope it helps :D!

Explanation:

6 0
2 years ago
An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish
Snezhnost [94]

Answer:

7.1 m/s

Explanation:

First, find the time it takes for the fish to reach the water.

Given in the y direction:

Δy = 6.1 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.12 s

Next, find the velocity needed to travel 7.9 m in that time.

Given in the x direction:

Δx = 7.9 m

a = 0 m/s²

t = 1.12 s

Find: v₀

Δx = v₀ t + ½ at²

7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²

v₀ = 7.1 m/s

4 0
4 years ago
Read 2 more answers
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