All categories

3 years ago

If two objects are in thermal equilibrium, do they have the same thermal or internal energy?

Physics

1 answer:

Tpy6a [65]3 years ago

7 0

Answer:

Yes, they do have the same internal energy.

Explanation:

The thermal balance refers to when there is no heat transfer between the bodies and their surroundings i.e. the bodies and the environment are at the same temperature.

Suppose two bodies of different masses and different materials, each one of them is at a temperature of 25(° C), which is the same temperature as the temperature of the environment, if these two bodies are close to each other, there is also heat transfer as they are at the same temperature, in the absence of any type of energy that enter or exit in these bodies, the amount of internal energy will be equal in both bodies.

Note: when the internal energy of one of these bodies is increased, heat transfer will happen, always looking for the thermal balance.

You might be interested in

Help again i need it quick

Romashka [77]

Answer:

it seems that the answer should be 7.5 mph as the average

Explanation:

sorry i did (s x t) when it was (s/t)

3 0

3 years ago

Read 2 more answers

After polishing his 2-kg wrestling trophy, Mike sets it down on the ground and walks away to find more polish. Meanwhile, Julie

klio [65]

1) The initial momentum of the trophy is zero

2) The initial momentum of the bowling ball is 160 kg m/s

3) The total momentum before the collision is 160 kg m/s

4) The total momentum of the system after the collision is 160 kg m/s

5) The final velocity of the trophy is 32 m/s

Explanation:

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

In this problem, the data for the trophy before the collision are:

m = 2 kg is the mass

v = 0 is its initial velocity

Therefore, the initial momentum of the trophy is

$p_1=(2)(0)=0$

Using the same equation used in part 1), the initial momentum of the bowling ball is

$p=mv$

where

m is the mass of the bowling ball

v is its initial velocity

The data of the problem are

m = 8 kg is the mass

v = 20 m/s is the velocity

Substituting,

$p_2=(8)(20)=160 kg m/s$

The total momentum of the system before the collision is given by the sum between the initial momentum of the trophy and the initial momentum of the bowling ball:

$p_i = p_1 + p_2$

where

$p_1$ is the initial momentum of the trophy

$p_2$ is the initial momentum of the ball

Here we have

$p_1 = 0$

$p_2 = 160 kg m/s$

Therefore, the total momentum is

$p_i = 0 + 160 = 160 kg m/s$

According to the law of conservation of momentum, for an isolated system (=no external unbalanced forces acting on the system), the total momentum of the system is conserved before and after the collision:

$p_i = p_f$

where

$p_i$ is the total momentum before the collision

$p_f$ is the total momentum after the collision

If we consider the system in the problem to be isolated (i.e. no frictional forces acting on the ball or the trophy), we can therefore say that the total momentum after the collision must be equal to the total momentum before the collision: therefore,

$p_f = 160 kg m/s$