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3 years ago

Practice

Physics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

The answer is Letter B The car travel at a constant veloc

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What is potential energy?

GenaCL600 [577]

Answer:

energy that is stagnant and cannot be changed

4 0

3 years ago

Read 2 more answers

A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T th

N76 [4]

The mass of the ion is 5.96 X 10⁻²⁵ kg

<u>Explanation:</u>

The electrical energy given to the ion Vq will be changed into kinetic energy $\frac{1}{2}mv^2$

As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force $\frac{mv^2}{r}$ .

So,

$Vq = \frac{1}{2}mv^2$

and

$Bqv = \frac{mv^2}{r}$

Right from these eliminating v, we can derive

$m = \frac{B^2r^2q}{2V}$

On substituting the value, we get:

$m = \frac{(0.4)^2X (0.305)^2 X1.602X 10^-^1^9}{2X 2000}\\\\$

m = 5.96 X 10⁻²⁵ kg.

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3 years ago

A planar electromagnetic wave is propagating in the +x direction. At a certain point P and at a given instant, the electric fiel

Free_Kalibri [48]

Answer:

$B=2.74\times 10^{-10}\ T$

Explanation:

It is given that,

A planar electromagnetic wave is propagating in the +x direction.The electric field at a certain point is, E = 0.082 V/m

We need to find the magnetic vector of the wave at the point P at that instant.

The relation between electric field and magnetic field is given by :

$c=\dfrac{E}{B}$

c is speed of light

B is magnetic field

$B=\dfrac{E}{c}\\\\B=\dfrac{0.082}{3\times 10^8}\\\\B=2.74\times 10^{-10}\ T$

So, the magnetic vector at point P at that instant is $2.74\times 10^{-10}\ T$ .

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3 years ago

What are the measurements that are used to<br><br> describe movement?

Feliz [49]

Answer: The SI unit

Explanation: The SI units are used to describe the distance an object moves

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2 years ago

If kinetic energy of a body is decreased by 10percent then decrease in linear momentum of that body

algol [13]

Answer:

E = 1/2 M V^2 = 1/2 P V since P = M V

E2 / E1 = P2 V2 / (P1 V1)

P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1

E2 / E1 = V2^2 / V1^2

V2 / V1 = (E2 / E1)^1/2

V2 / V1 = (.9)1/2 = .95

The linear momentum would have to decrease by 5%

7 0

2 years ago