3 years ago

Practice

Physics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

The answer is Letter B The car travel at a constant veloc

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At t = 0, object A is dropped from the roof of a building. At the same instant, object B is dropped from a window 10 m below the

dsp73

Answer:

Explanation:

Given two objects are dropped simultaneously

Object A is 10 m higher than object B therefore

Distance covered by object A is given by

$y_a(t)$ is given by

$y=ut+\frac{1}{2}at^2$

where y=displacement

u=initial velocity

a=acceleration

t=time

$y_a(t)=0+0.5gt^2--1$

for object B

$y_b(t)=0+0.5gt^2--2$

Subtract 1 and 2 we get

$y_a(t)-y_b(t)=0$

i.e. they will travel equal distance in equal time and distance between them remain 10 m until object B hits the ground

4 0

3 years ago

A fire breaks out and increases the Kelvin temperature of a cylinder of compressed gas by a factor of 2.4. What is the final pre

kherson [118]

Answer:

P(final) is 2.4 times P(initial).

Explanation:

Here we can assume that the cylinder did not break and it's volume and number of moles of gas present in the cylinder remains constant.

Given the temperature increases by a factor of 2.4. Let us assume that the initial temperature be $T_{1}$ and the final temperature be $T_{2}$ .

Given that $T_{2}=2.4\times T_{1}$

Now we know the ideal gas equation is PV=nRT

here V=constant , n=constant , R=gas constant(which is constant).

$\frac{P}{T}=constant$

$\frac{P_{1} }{T_{1}}=\frac{P_{2} }{T_{2} }$

$P_{2}=(\frac{T_{2} }{T_{1} } )P_{1}$

$P_{2}=(\frac{2.4T_{1} }{T_{1} } )P_{1}$

$P_{2}=2.4\times P_{1}$

7 0

3 years ago

A student walks 4 blocks east, 7 blocks west, 1 block east and then 2 blocks west in an hour what is their velocity

Nutka1998 [239]

Answer:

4 blocks west is final displacement. So 4 blocks per hour

3 0

2 years ago

a ball is thrown horizontally from a 20 m high building with a speed of 5.0 m/s. How far from the base of the building does the

kipiarov [429]

Given:
Dy= 20 m
Vi = 5.0 m/s horizontally
A=9.81 m/s^2

Find:
Horizontal displacement

Solution:
D=ViT+(1/2)AT^2
Dy=(1/2)AT^2
T^2=Dy/(1/2)A
T=sqrt(Dy/(1/2)A)
T=sqrt(20/4.905)
T=2.0s

Dx=ViT
Dx=(5.0)(2.0)
Dx=10. meters

7 0

3 years ago

Pls help i’ll give brainliest if you give a correct answer!!

arsen [322]

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

3 0

3 years ago

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