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3 years ago

Can anyone help? find the value of x (test) due at 3pm

Mathematics

1 answer:

erik [133]3 years ago

7 0

Answer:

omg I hate that

Step-by-step explanation:

use photo math or something!

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43.0129 to the nearest hundredths

S_A_V [24]

Answer:

43.01

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The guidance department has reported that of the senior class, 2.3% are members of key club, K, 8.6% are enrolled in AP physics,

Levart [38]

P(P|K) = 82.6%.

P(P|K) = P(K and P)/P(K) = 1.9%/2.3% = 0.019/0.023 = 0.8261 = 82.6%

4 0

3 years ago

Read 2 more answers

A researcher interested in vocabulary development obtains a sample of twenty 3-year old children to participate in a research st

Andreyy89

Answer: b) statistic

Step-by-step explanation:

Population = A large groups of individuals sharing the same or similar characteristic by the point og study.
Sample = It is a subset of population .
Parameter = It is measure of characteristic in population.
Statistic = It is measure of characteristic in sample.

Since the average score was taken by the group of 20 which is nothing but the sample.

That means, the average score is an example of<u> statistic</u>.

Hence, the correct option is b) statistic .

4 0

3 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago

Mrs. Frazier had 95 inches of ribbon. She gave 14.4 inches to Sara and 27.8 inches to Mary. If she divides the remainder between

Dmitry_Shevchenko [17]

Answer:

26.4

Step-by-step explanation:

95-14.4-27.8=52.8

52.8/2=26.4

Hope I helped!

Please mark Brainliest!!!

3 0

3 years ago