Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
1) |−11| = 11, therefore Peter is at a distance of 11 feet
2) Jimmy, because each of the two points is fraction 5 over 8 unit away from 0
3) 36 + 28=64 4x4=36+4x7=28 36+28=64
7+9=16 4x16=64
By taking a subtraction, we will see that the change that Kate receives is $1.08
<h3>
</h3><h3>
How to get the change?</h3>
The change will be given by the difference between what Kate has, and the cost of all the items she buys.
She has $20.00, and the costs are: $6.99, $3.98, and $7.95.
Then the change will be:
C = $20.00 - $6.99 - $3.98 - $7.95 = $1.08
We conclude that the change is $1.08
If you want to learn more about subtractions, you can read:
brainly.com/question/2475734
Step-by-step explanation:
2tan∅=10.25
Tan∅= 10.25/2
∅= 78.95
Answer:
15
Step-by-step explanation:
the answer is 15 because opposite angles are congruent so 5x15=75
